an object placed in a fluid sinks and displaces a volume of fluid. what is the relationship between the volume of the object?

Why would concentrated hydrochloric acid be a poor choice as the acid catalyst for the formation of cyclohexane by dehydration o

babunello [35]

Answer:

Chlorine ion will attack the carbocation and double bond will not be created

Explanation:

The use of concentrated hydrochloric acid wiill be a poor choice as the acid catalyst for the formation of cyclohexane by dehydration of cyclohexanol because of the following reasons:

1) There will be presence of chlorine ions and they will attack the carbocation to form a single bond.

2) The formation of double bond will not occur in the process.

Therefore, it is a poor choice to use concentrated hydrochloric acid as the acid catalyst for the formation of cyclohexane by dehydration of cyclohexanol.

6 0

3 years ago

03/08/2020

Tanzania [10]

Explanation:

According to your question, 

no. a. ans would be like; chemical formula is defined as the an expression which determines no. and type of molecule of a compound. 

b. no. ans; it tells that what type of compound is formed with the type and no. of atoms present in the atom.

c. no ans; the formulation of h2so4 states that it is acid named as hydrochloric acid which is formed by reacting of hydrogen (2 atoms ) ,sulpher (*1atom) and oxygen(4atoms).

Hope it helps...

8 0

3 years ago

) B5H9(l) is a colorless liquid that will explode when exposed to oxygen. How much heat is released when 0.211 mol of B5H9 react

Tom [10]

Answer: The amount of heat released when 0.211 moles of $B_5H_9(l)$ reacts is 554.8 kJ

Explanation:

The chemical equation for the reaction of $B_5H_9$ with oxygen gas follows:

$2B_5H_9(l)+12O_2(g)\rightarrow 5B_2O_3(s)+9H_2O(l)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(5\times \Delta H_f_{(B_2O_3(s))})+(9\times \Delta H_f_{(H_2O(l))})]-[(2\times \Delta H_f_{(B_5H_9(l))})+(12\times \Delta H_f_{(O_2(g))})]$

We are given:

$\Delta H_f_{(H_2O(l))}=-285.4kJ/mol\\\Delta H_f_{(B_2O_3(s))}=-1272kJ/mol\\\Delta H_f_{(B_5H_9(l))}=73.2kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(2\times (-1272))+(9\times (-285.4))]-[(2\times (73.2))+(12\times (0))]\\\\\Delta H_{rxn}=-5259kJ$

To calculate the amount of heat released for the given amount of $B_5H_9(l)$ , we use unitary method, we get:

When 2 moles of $B_5H_9(l)$ reacts, the amount of heat released is 5259 kJ

So, when 0.211 moles of $B_5H_9(l)$ will react, the amount of heat released will be = $\frac{5259}{2}\times 0.211=554.8kJ$

Hence, the amount of heat released when 0.211 moles of $B_5H_9(l)$ reacts is 554.8 kJ

7 0

3 years ago

SICL4 + H2O sio2 hcl

atroni [7]

Do you want this equation balanced?

If so, it would be

SiCl4 + 2H2O ---> SiO2 + 4HCl

5 0

3 years ago

What is a limitation of solar power?

kodGreya [7K]

A is correct .

please vote my answer brainliest. thanks!

3 0

3 years ago