The answer is London dispersin forces and dipole-induced dipole forces.
The London dispersion force is a temporary attractive force that results
when the electrons in two adjacent atoms occupy positions that make the
atoms form temporary dipoles. This force is sometimes called an induced
dipole-induced dipole attraction. This force is found in any compound and is the weakest atraction force between atoms or molecules.
Those temporay dipoles are not like the dipoles that form the polar molecules, because the polar molecules are the result of permanent dipoles.
<span>the polarity of the solute or the solvent.
for example:
oil will not mix with water because oil molecules are nonpolar however water moleculses are polar. so, they will not mix with each other.
when we put sodium chloride in water, sodium chloride will be easily dissoved. because both sodium chloride and water are polar.
in other case, if we put sodium chloride and hexane together. sodium chloride will not dissove in hexane, because hexane is a nonpolar solvent.
finally, if we try to mix hexane and bromine together, they will mix uniformly. because both hexane and bromine are nonpolar. (note: most diatomic molecules are nonpolar, such as hydrogen gas, oxygen gas, chlorine gas, etc. )
so just remember, nonpolar and nonpolar will dissovle each other. and polar and polar will dissolve each other.</span>
Answer:
1.09 mL
Explanation:
Density is a measure of a substance's mass over its volume.
d = m/v
We can rearrange the equation to solve for volume, using algebra.
v = d/m
Therefore v = 6.35/5.80 = 1.09 mL
Answer:
1.05 L
Explanation:
There is some info missing I think this is the original question.
<em>A laboratory experiment requires 250 millimeters of water boiling. it also requires 100 mills of water for a cooling process. If a student performs the experiment three times, how much total water will the student need? Give your answer in liters.</em>
<em />
Step 1: Calculate the volume required for each experiment.
The volume required is the sum of the volumes used: 250 mL + 100 mL = 350 mL
Step 2: Calculate the volume required for the 3 experiments
We have to multiply the volume required for each experiment by 3.
3 × 350 mL = 1050 mL
Step 3: Convert the volume to liters
We use the relation 1 L = 1000 mL.
1050 mL × (1 L/1000 mL) = 1.05 L
