If you would like to know what is your average speed, you can calculate this using the following steps:
1 3/4 miles = 7/4 miles ...half an hour
7/4 miles * 2 = 7/2 miles = 3 1/2 miles ... one hour
Result: Your average speed is 3 1/2 miles per hour.
Answer:

Step-by-step explanation:
Deepak charges for each Job = $30
An additional charges for working each hour = $15
Let x be the number of hours he worked for each job.
So,additional charges for working x hours = 15 x
So,he earns in total at each job = 
We are also given that He only accepts jobs if he will earn at least $90 the job.
This means he must earn $90 or more than that .
So, the inequality becomes:

Hence an inequality to determine x, the number of hours he must work during each job in order to accomplish this is 
The answer would be b). -4
Reason being you have to minus four dollars to get to 14. If you chose c, then you would be adding four dollars, which isn't right. So your answer is b.
Answer:
x = 50.8°
Step-by-step explanation:
We are given:
1.) Angle x
2.) Side opposite to angle x
3.) Hypotenuse
Therefore to find the angle x, we will use the sin inverse:
<em>Sin(x) = Opposite / Hypotenuse</em>
Sin(x) = 6.2/8
x = Sin⁻¹(6.2/8)
<u>x = 50.8°</u>
Hope this helps!
Answer:
- 45 regular keyboards
- 15 wireless keyboards
Step-by-step explanation:
A set of 3 regular and 1 wireless keyboard would sell for ...
3×$83 +110 = $359
For the given sales, the number of sets sold was ...
$5385/($359/set) = 15 sets
Since there are 3 regular keyboards in each set, there were 3×15 = 45 regular keyboards sold. The number of each type of keyboards sold is ...
45 regular keyboards and 15 wireless keyboards
_____
<em>Comment on this solution</em>
When a problem statement tells you the ratio of one kind of item to another, it is often convenient to group the items in that ratio and deal with the groups. Sometimes, there will be a few missing or left over, for example "10 more than 3 times as many." In those cases, you can make an adjustment to the total and still deal with the groups. (Any equations you might write will effectively do this same thing.)