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erik [133]
3 years ago
10

ABC has vertices of A(0, 0), B(–4, 0), and C(–2, 4). The coordinates of each vertex are multiplied by 3 to create AEF. Determine

if ABC is similar to AEF. Explain your answer.
A. No, they are not similar because the corresponding angles are not congruent.
B. No, they are not similar because the corresponding sides are not proportional.
C. Yes, they are similar with a scale factor of 1:3.
D. Yes, they are similar with a scale factor of 0:3.
Mathematics
2 answers:
Andrej [43]3 years ago
7 0

Answer:

Option C is right

Step-by-step explanation:

Given that ABC has vertices of A(0, 0), B(–4, 0), and C(–2, 4).

When coordinates are multiplied by 3, to create AEF, we get new coordinates as

A(0,0) B(-12,0) and C(-6,12)

Comparing the sides we have

AB = 4 and A'B' =12\\AC=\sqrt (4+16) = 2\sqrt 5\\A'C' =\sqrt (36+144) = 6\sqrt 5

BC= \sqrt (4+16) = 2\sqrt 5\\B'C' =\sqrt(36+144) = 6\sqrt 5

Thus we find that Sides of ABC are proportional to A'B'C'

Hence they are similar with scale factor of 3

Option C is right.

o-na [289]3 years ago
6 0
That statement that determine if ABC is similar to AEF and base on the data and the vertices in the given problem. The statement that best describe the two triangle is letter C. Yes, they are similar with a scale factor of 1:30. I hope you are satisfied with my answer. 
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Rama09 [41]

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7 0
3 years ago
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marissa [1.9K]

Answer:

option b)

tan²θ + 1 = sec²θ

Step-by-step explanation:

The Pythagorean trigonometric identity is a trigonometric identity expressing the Pythagorean theorem in terms of trigonometric functions.

hypotenuse² = height² + base²

Given in the questions are some pythagorus identities which except of b) are all incorrect as explained below.

<h3>1)</h3>

sin²θ + 1 = cos²θ     incorrect

<h3>sin²θ + cos²θ = 1 correct</h3><h3 /><h3>2)</h3>

by dividing first identity by cos²θ

sin²θ/cos²θ + cos²θ/cos²θ = 1/cos²θ

<h3>tan²θ + 1 = sec²θ  correct</h3><h3 /><h3>3)</h3>

1 - cot²θ = cosec²θ  incorrect

by dividing first identity by sin²θ

sin²θ/sin²θ + cos²θ/sin²θ = 1/sin²θ

<h3>1 + cot²θ = cosec²θ correct</h3><h3 /><h3>4)</h3>

1 - cos²θ  = tan²θ

not such pythagorus identity exists

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3 years ago
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