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3 years ago

PLEASE HELP MEEEEEEEEEEEEEEEEEEEEEE

Mathematics

1 answer:

dezoksy [38]3 years ago

6 0

45+35=80

100-80=20

360×20/100

72 so the answer is this and the formula E=T×%/100

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A seed company planted a floral mosaic of a national flag. The perimeter of flag is 2,340 ft determine the flag’s width and leng

Natali5045456 [20]

Answer:

Width: 450 feet

Length: 720 feet

Step-by-step explanation:

So we start with the equation to find the perimeter -

2l + 2w = p

l = length

w = width

p = perimeter

We insert the 2,340 ft as the perimeter -

2l + 2w = 2,340 ft

Now we find another equation for the "length is 270 ft greater than width" -

l = 270 ft + w

Using substitution, we substitute the y in the first equation with 270 ft + w -

2 (270 ft + w) + 2w = 2,340 ft

540 ft + 2w + 2w = 2,340 ft

540 ft + 4w = 2,340 ft

4w = 2,340 ft - 540 ft

4w = 1,800 ft

w = 1,800 ft / 4

w = 450 ft

Now to find the width we substitute the w with 450 ft -

l = 270 ft + w

l = 270 ft + 450 ft

l = 720 ft

Check -

2 * 720 ft + 2 * 450 ft = 2,340 ft

1,440 ft + 900 ft = 2,340 ft

2,340 ft = 2,340 ft (Correct)

3 0

3 years ago

Help me with this geometey question !! thanks!

Reptile [31]

Answer:

A=542

Step-by-step explanation:

none, sorry

6 0

3 years ago

Read 2 more answers

9 + 15m factorisation of algebraic expression that contain common factor

Svet_ta [14]

The common factor would be 3 because 3 is the highest multiple of 15 and 9

6 0

3 years ago

Read 2 more answers

In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day

nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

$P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33$

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

$P(A \cap B) = 0.42*0.25 = 0.105$

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

$P(B|A) = \frac{0.105}{0.33} = 0.3182$

31.82% probability that this day would be a winter day

6 0

3 years ago

What is true regarding two adjacent arcs created by two intersecting diameters?

Juli2301 [7.4K]

Given:

Two diameters intersect each other.

To find:

The correct statement regarding two adjacent arcs created by two intersecting diameters.

Solution:

We know that, two diameter intersect each other at origin and measure of arc is equal to the corresponding angle generated by the intersection of diameters.

If two lines intersect each other then we get 4 angles and sum of any two adjacent angles is 180°.

It means the sum of any two adjacent central angles generated by the intersection of diameters is 180°.

So, the sum of two adjacent arcs created by two intersecting diameters is 180°.

Therefore, the correct option is C.

7 0

2 years ago