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sineoko [7]
3 years ago
14

-4log(2x) = -8 if someone can help me with this problem i’ll venmo them 2$

Mathematics
1 answer:
Temka [501]3 years ago
5 0
X=50
You can keep ur 2 dollars but I’m not explaining it
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Rueben sells electronics. He earns a 5% commission on each sale he makes. If Ruben wants to make $100 in commission, what is the
Alecsey [184]

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It is 20

Step-by-step explanation:

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3 years ago
What is the reciprocal of 9/10 as a mixed numeral?
Alika [10]
Reciprocals are technically flipped fractions. So it would be 10/9. 9 goes into ten one time, so it's 1 1/9.
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A school staff meeting had 36 teachers in attendance, 75% of whom were first-year teachers. How many first-year teachers were in
natita [175]

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27

Step-by-step explanation:

First, lets write this down, 36 x 75%, then lets convert the percent: 36 x .75, multiply! And we get 27.

8 0
3 years ago
Read 2 more answers
A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each
Nadya [2.5K]

Answer:

312.5\pi \text{ km}^3\approx 981.75\text{ km}^3

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}, where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3

Therefore, the volume of earth removed to build the three tunnels is 312.5\pi \text{ km}^3\approx 981.75\text{ km}^3.


4 0
3 years ago
I dont understand this at all. I really need help! ​
Westkost [7]

Hello!

\large\boxed{x^{4}}

Recall that:

\sqrt[z]{x^{y} } is equal to x^{\frac{y}{z} }.  Therefore:

\sqrt[3]{x^{2} } = x^{\frac{2}{3} }

There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:

(x^{\frac{2}{3} })^{6}  = x^{\frac{2}{3}* 6 }  = x^{\frac{12}{3} } = x^{4}

3 0
3 years ago
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