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2 years ago

PLS HELP!! WILL MAKE BRAINLIEST!!!!

Mathematics

1 answer:

Nitella [24]2 years ago

7 0

To find slope the formula is y1-y2/x1-x2

-7-14 -21

______. = ------- = 7

-7+4 -3

Slope is 7, thank you for the brainliest

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Please help me show my work for, Larry has a piece of wood that is 2.45 feet long and 2.097 inches wide. Part B: Using the width

Lelechka [254]

Answer: 0.43ft²

Step-by-step explanation:

You didn't really specify part A but In assuming that the question you posted is part A. Anyways in this case, area will be calculated by multiplying the length by the width.

Since the piece of wood has a length that is 2.45 feet and width that is 2.097 inches, then the area will be:

= 2.45 × 0.17475

= 0.4281375 ft²

= 0.43ft² to nearest hundredths

Note 1 foot = 12 inches

Therefore, 2.097 inches = 2.097/12 = 0.17475 feet

5 0

3 years ago

Look at the sequence in the table.

malfutka [58]

Answer:

Step-by-step explanation:

The consecutive values of $a_{n}$ have a common difference d, that is

d = 8 - 3 = 13 - 8 = 18 - 13 = 23 - 18 = 5

This indicates that the sequence is arithmetic.

The recursive formula allows the next term in the sequence to be found from the previous term by adding 5, thus

$a_{n}$ = $a_{n-1}$ + 5 → A

7 0

3 years ago

Use the distributive property to rewrite the expression: 5(3p -8)

makkiz [27]

Answer:

15p-40

Step-by-step explain

i think is this

8 0

2 years ago

Read 2 more answers

The area of a rectangle is 3/8 in and the length is 5/8 What is the width?

liberstina [14]

Answer:

The width W is :

$W=\frac{3}{5}$

Step-by-step explanation:

Let A be the area of the rectangle

Let L be the length of the rectangle

Let W be the width of the rectangle

______

Formula:

A = L × W

__________

$\begin{aligned}A &=L \times W \\\Rightarrow W &=\frac{A}{L} \\\Rightarrow W &=\frac{\frac{3}{8}}{\frac{5}{8}} \\&=\frac{3}{8} \times \frac{8}{5} \\&=\frac{3 \times 8}{8 \times 5} \\&=\frac{3}{5}\end{aligned}$

6 0

2 years ago

Alejandra's Tapas Bar offers a menu consisting of $9$ savory and $5$ sweet dishes. You can also get a mix-and-match plate consis

Mariana [72]

Answer:

Step-by-step explanation:

Given that the number of savory dishes is 9 and the number of sweet dished is 5.

Denoting all the 9 savory dishes by $p_1, p_2,...,p_9$ , and all the sweet dishes by $q_1,q_2,...,q_5$ .

The possible different mix-and-match plates consisting of two savory dishes are as follows:

There are 9 plates with $q_1$ from sweet plates which are $(q_1, p_1), (q_1, p_2), ..., (q_1,p_9).$

There are 9 plates with $q_2$ from sweet plates which are $(q_2, p_1), (q_2, p_2), ..., (q_2,p_9).$

Similarly, there are 9 plated for each $q_3, q_4$ and $q_5.$

Hence, the total number of the different mix-and-match plates consisting of two savory dishes

$= 9+9+9+9+9= 9\times5=45$

7 0

3 years ago