Answer:
period of oscillations is 0.695 second
Explanation:
given data
mass m = 0.350 kg
spring stretches x = 12 cm = 0.12 m
to find out
period of oscillations
solution
we know here that force
force = k × x .........1
so force = mg = 0.35 (9.8) = 3.43 N
3.43 = k × 0.12
k = 28.58 N/m
so period of oscillations is
period of oscillations = 2π ×
................2
put here value
period of oscillations = 2π ×
period of oscillations = 0.6953
so period of oscillations is 0.695 second
Answer:
8.829 m/s²
Explanation:
M = Mass of Earth
m = Mass of Exoplanet
= Acceleration due to gravity on Earth = 9.81 m/s²
g = Acceleration due to gravity on Exoplanet



Dividing the equations we get

Acceleration due to gravity on the surface of the Exoplanet is 8.829 m/s²
D. a membrane bound nucleus , lmk if im right
Explanation:
Given that,
Initial velocity, u = 11.3 m/s
Angle above the horizontal, 
Time of flight :

Horizontal distance traveled is given by :
x = ut
x = 11.3 m/s × 1.32 s
x = 14.916 m
Maximum height is given by :

Hence, time of flight is 1.32 s, horizontal distance is 14.916 m and maximum height is 2.14 m.