suman ek din maxi pahankar peshab ma hath dali thi
Applying force all the time is bad for you body, the object, and the environment and how it looks at you. First of all, you could strain, break, fracture, you name it, to your bones and muscles. Second of all, you could manage to break that object, not even move it. For example, say you have to move a heavy object to save the town from almost flooding and you strain or break your arm. To society or the people watching you do this, you look like a wimp or you're not strong. Then you have a bad reputation in the people's eyes and you get picked on or bullied because of that. You don't have move that object. You could find a way to work around the object and get simpler ways that only you thought of at the time.
Answer:
Correct answer: F = 214.56 N
Explanation:
Given:
V₀ = 0 m/s initial speed
V = 44.7 m/s speed after t = 29 seconds
m = 96 kg
F = ? horizontal force
Taking off an airplane is a uniformly accelerated motion to which the formula applies:
V = V₀ + a t and V₀ = 0 m/s
V = a t ⇒ a = V / t = 44.7 / 20 = 2.235 m/s²
a = 2.235 m/s²
the horizontal force is calculated using the formula:
F = m · a = 96 · 2.235 = 214.56 N
F = 214.56 N
God is with you!!!
Using the theorem of kinetic energy
1/2mVf² - 1/2mVi²= WF + Wp, Wp=0
WF = F. AB, AB=5m and F= 40N, m=20kg
so the final kinetic is KEf= 1/2mVf² = WF =<span>F. AB= 40*5=200J
</span>
the final velocity is 1/2mVf² <span>=200, implies Vf= sqrt(20)=2sqrt(5)m/s</span>
Answer:
Time interval;Δt ≈ 37 seconds
Explanation:
We are given;
Angular deceleration;α = -1.6 rad/s²
Initial angular velocity;ω_i = 59 rad/s
Final angular velocity;ω_f = 0 rad/s
Now, the formula to calculate the acceleration would be gotten from;
α = Change in angular velocity/time interval
Thus; α = Δω/Δt = (ω_f - ω_i)/Δt
So, α = (ω_f - ω_i)/Δt
Making Δt the subject, we have;
Δt = (ω_f - ω_i)/α
Plugging in the relevant values to obtain;
Δt = (0 - 59)/(-1.6)
Δt = -59/-1.6
Δt = 36.875 seconds ≈ 37 seconds
