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Sergio [31]
3 years ago
11

Why would a rocket fall vertically downwards if it was launched vertically upwards​

Physics
1 answer:
IgorC [24]3 years ago
3 0

Answer:

It would because the shape of the rocket is designed to be able to slice through the air as smooth as possible and now you may be thinking that air is already smooth but when you try to push something as large and heavy like a rocket then the shape of the rocket will be very important. The bottom of the rocket is flatter then the top so it is not designed to fly smoothly through the air. So the rocket would fall vertically downward(If it was still in one piece)because of it's shape. It is easier for the top of the rocket to go smoothly through the air then the bottom.

Explanation:

I am 90% sure this is correct but if I'm not please tell me

You might be interested in
Think of an example that you could use to convice a friend that an object at rest has an "internal hold back property" that is d
zmey [24]

Answer:

Explanation:

There are various examples around us that states " internal hold back property " and is different from frictional force or the force of Earth's gravity.

The plaster which is the mixture of cement and water has an adhesive nature and molecules inside them has a internal hold back property. They stick to the walls and ceiling and do not fall.

Though gravity is applied on it still its molecules tends to hold the ceiling firmly and do not fall upon.

7 0
4 years ago
A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio
Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be 8.21\times 10^3~N

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

5 0
4 years ago
In introductory physics laboratories, a typical Cavendish balance for measuring the gravitational constant G uses lead spheres o
SVETLANKA909090 [29]

Answer:

F = 7.7*10^{-10}N

Explanation:

You need to be careful with units for this problem. The force will be:

F =\frac{K*m1*m2}{d^2}

F=\frac{6.67259 * 10^{-11}*1.56*21.1*10^{-3}}{(5.34*10^{-2})^2}

F=7.7*10^{-10}N

8 0
3 years ago
It is very important to use _______ in your calculations
NeX [460]

Answer:

snoemw

Explanation:

4 0
3 years ago
A train moves at constant velocity of 90km/h. How far will it go in 0.25h.
enot [183]
In a quarter of an hour it will travel 1/4 x 90 = 22.5Km
8 0
3 years ago
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