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2 years ago

A committee consists of 8 men and 11 women. In how many ways can a subcommittee of 3 men and 5 women be chosen?

Mathematics

1 answer:

PIT_PIT [208]2 years ago

8 0

Answer:

25872 ways

Step-by-step explanation:

We're choosing 5 women from a group of 11 and 3 men from a group of 8. We don't care about what order they are picked and so we'll use the combination formula, which is:

n!/(k!)(n-k)! with n as population and k as picks.

We'll multiply the results together. (8! / (3!)(8-3)!) * (11! / (5!)(11-5)!)

That equals: (8! / (3!)(5!) ) * (11! / (5!)(6!)) = 40320/(6x120) * 39916800/ (120x720)

56 * 462 = 25872

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Step-by-step explanation:

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2 years ago

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Which choice models this situation? Fahad needs to sell 25 tickets to a fundraiser by Friday. So far, he has sold 9 tickets. How

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Answer:

16 tickets

Step-by-step explanation:

Number of tickets he has to sell = 25

Number of tickets he has sold = 9

How many tickets does he still need to sell?

Number of tickets he still needs to sell = Number of tickets he has to sell - Number of tickets he has sold

= 25 - 9

= 16 tickets

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3 years ago

Change the following improper to mixed plz help quick! 1. 8/3 2. 9/4 3. 12/5

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Answer:

Improper Fractions:

Step-by-step explanation:

1. 2 and 2/3

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2 years ago

In the U.S., 95% of children have received their DTaP vaccine. Calculate the probability that fewer than 700 out of a sample of

Studentka2010 [4]

Answer:

0.0183

Step-by-step explanation:

The percentage of students, who received their DTaP vaccine is 95%.

This implies that:

$p = 0.95$

and

$q = 1 - 0.95 = 0.05$

The standard deviation of the proportion is

$= \sqrt{ \frac{pq}{n} }$

$= \sqrt{ \frac{0.95 \times 0.05}{750} } \\ = 0.00796$

We want to find the probability, that the sample proportion,

$\hat p \leqslant \frac{700}{750} \\ \hat p \leqslant 0.9 \bar3$

$P(\hat p\le0.9\bar3)=P(Z\le \frac{0.9 \bar3 - 0.95 }{0.00796} ) \\ = P(Z\le - 2.09) \\ = 0.0183$

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3 years ago

Find the sum of the counting numbers from 1 to 25 inclusive. In other words, if S = 1 + 2 + 3 + ... + 24 + 25, find the value of

Anastaziya [24]

Answer:

325

Step-by-step explanation:

You must have heard about Arithmetic Progressions (AP)

Arithmetic progressions are a series of numbers such that every successive number is the sum of a constant number and the previous number.

Our very own counting numbers form AP

For example :-

2 = 1 + 1

3 = 2 + 1

4 = 3 + 1

The number in bold (1) is that constant number which is added to a number to form its successive number.

To find the sum of series forming AP, we use the formula :-

$sum = \frac{n}{2} \{ a + a _{n} \}$

here,

n is the number of terms
a is the first number of the series
an is the last number of the series

So we'll use all this information to find the sum of continuous numbers from 1 to 25 where 1 is the first term(a) and 25 is the last(an).

and n is 25

$S = \frac{25}{2}\{ 1 +25\}$

$= \frac{25 \times 26}{2}$

$= 25 \times 13$

$= 325$

So, the value of S comes out to be 325.

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2 years ago

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