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serious [3.7K]
2 years ago
15

A committee consists of 8 men and 11 women. In how many ways can a subcommittee of 3 men and 5 women be chosen?

Mathematics
1 answer:
PIT_PIT [208]2 years ago
8 0

Answer:

25872 ways

Step-by-step explanation:

We're choosing 5 women from a group of 11 and 3 men from a group of 8. We don't care about what order they are picked and so we'll use the combination formula, which is:

n!/(k!)(n-k)! with n as population and k as picks.

We'll multiply the results together. (8! / (3!)(8-3)!) * (11! / (5!)(11-5)!)

That equals: (8! / (3!)(5!) ) * (11! / (5!)(6!)) = 40320/(6x120) * 39916800/ (120x720)

56 * 462 = 25872

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-29 (the temperature in Duluth) is closer to 0, because 29 is less than 31.

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How many decibels is this? show work​
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Explanation:

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3 years ago
The purpose of a battery in a circuit is to _____.
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Answer:

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Step-by-step explanation:

Hope this is correct

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7 0
2 years ago
Please help! If possible please show your work. Thank you in advance!! :D
Rudiy27

Answer:

  • (-4)³ = -64
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Step-by-step explanation:

The first step in solving the equation is to cube both sides:

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__

We're not sure what "checking" is supposed to involve here. Usually, one would check the answer by seeing if a true statement is made when the answer is put into the original equation.

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Many calculators will not compute √(-64) because they compute roots using logarithms. The log of a negative number is not defined.

So, the way one would check this is to cube both sides, which is how we got the answer in the first place. We expect the same result from doing the same operation again, so it isn't really a check.

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