<h2>♪Answer : </h2>
»f(x) = 9(9 + x)(10)
subtitute x = 2 for f(x).
»f(5) = 9(9 + 5)(10)
»f(5) = 9(14)(10)
»f(5) = 1,260✅
The answer should be -3xy^2 (4x^2y^3 + 3x - 4y)
Answer: -1
The negative value indicates a loss
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Explanation:
Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)
There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die
There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18
Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event.
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9
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In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9
The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9
Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7
Add up those results
3+3+(-7) = -1
The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.
Note: because the expected value is not 0, this is not a fair game.
Answer:
= 8sqrt2
Step-by-step explanation:
Area of a trapezium is given by the formula;
1/2(a+b)h
;
Where a and b are the parallel sides and h is the perpendicular height.
a = 3 cm, b= 5 cm
To get; h, we use the Pythagoras theorem;
h² = 3² - 1²
h² = 8
h = √8
= √4√2
= 2√2
Thus;
Area = 1/2(3 +5) 2√2
= 1/2 ×8 × 2√2
<u> = 8√2 cm² or 8sqrt2 cm²</u>
3.c - 8 = 5
(3.c - product of 3 and a number)
(-8 : 8 less)
