Answer:

Step-by-step explanation:
we know that
The area of a circle is equal to

In this problem we have

Substitute and find the area

Remember that
subtends the area of complete circle
so
by proportion
Find the area of the shaded regions
The central angle of the shaded regions is equal to 

Answer:
the horizontal position for the left edge of the image is -4.46 cm.
Step-by-step explanation:
The horizontal midpoint of the page is:
21.59 / 2 = 10.79 cm
The horizontal midpoint of the image is given as:
30.51 / 2 = 15.25 cm
These midpoints must be on the same point in the axis.
By taking the leftmost edge of the paper to be point zero on the axis, then, the distance accommodated by the paper is 10.795 cm.
The distance that goes beyond this leftmost edge is computed as;
This is on the negative side on the axis.
Thus the horizontal position for the left edge of the image is -4.46 cm.
Answer:
Smaller angle = 53.2
Larger angle = 126.8
Step-by-step explanation:
Lets say x is the measure of the supplement. Since we know they're supplementary, we know their angle measure sum will equal 180. We can set up our equation like this
. Note: (x - 73.6) is the measure of the smaller angle. By solving, we get 126.8 degrees for the measure of the supplement. If we plug in the value of x into (x-73.6), we get 53.2 degrees as the angle measure of the smaller angle.
Answer:
b
Step-by-step explanation:
Answer:
The mean of samples of 100 IQ scores taken out from this population will have a distribution with mean M=104 and standard deviation s=3.5.
Step-by-step explanation:
We know the population mean and standard deviation, that has a bell-shaped distribution:

The sampling distribution, the distribution of the mean of samples of size n out of this population, will have the same mean as the population mean.

The standard deviation will be related to the population standard deviation and the sample size as:

Then, the mean of samples of 100 IQ scores taken out from this population will have a distribution with mean M=104 and standard deviation s=3.5.