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Vitek1552 [10]
3 years ago
8

Joelle is working on a school report in a word processor. She wants to place an oversized image which is 30.51 \text{ cm}30.51 c

m30, point, 51, start text, space, c, m, end text wide so that it appears centered on the page. The width of the page is 21.59 \text{ cm}21.59 cm21, point, 59, start text, space, c, m, end text. In the program, horizontal positions to the right of the leftmost edge of the page are positive. What horizontal position for the left edge of the image should Joelle use to center the image?
Mathematics
1 answer:
ehidna [41]3 years ago
3 0

Answer:

the horizontal position for the left edge of the image is -4.46 cm.

Step-by-step explanation:

The horizontal midpoint of the page is:

21.59 / 2 = 10.79 cm

The horizontal midpoint of the image is given as:

30.51 / 2 = 15.25 cm

These midpoints must be on the same point in the axis.

By taking the leftmost edge of the paper to be point zero on the axis, then, the distance accommodated by the paper is 10.795 cm.  

The distance that goes beyond this leftmost edge is computed as;

This is on the negative side on the axis.

Thus the horizontal position for the left edge of the image is -4.46 cm.

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Which system has no solutions?
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y > 6 and y < 2

Step-by-step explanation:

as the value of y can not be greater than 6 and less than 2 at the same time, the 2 inequalities have no common solutions

theefore no solution

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Find function inverse of f? F(x)=x+2/7
nignag [31]

Answer:

f’(x) = x -2/7

Step-by-step explanation:

Let f(x)= y

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y = x + 2/7

x = y-2/7

So the inverse f’(x) = x - 2/7

6 0
3 years ago
67. The line contains the point (4,0) and is parallel<br> to the line defined by 3x = 2y.
olganol [36]

Answer:

y=\frac{3}{2} x-6

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form:
  • y=mx+b where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)
  • Parallel lines will always have the same slope but different y-intercepts.

<u>1) Determine the slope of the parallel line</u>

Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

3x = 2y

Switch the sides

2y=3x

Divide both sides by 2 to isolate y

\frac{2y}{2} = \frac{3}{2} x\\y=\frac{3}{2} x

Now that this equation is in slope-intercept form, we can easily identify that \frac{3}{2} is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope \frac{3}{2} . Plug this into y=mx+b:

y=\frac{3}{2} x+b

<u>2) Determine the y-intercept</u>

y=\frac{3}{2} x+b

Plug in the given point, (4,0)

0=\frac{3}{2} (4)+b\\0=6+b

Subtract both sides by 6

0-6=6+b-6\\-6=b

Therefore, -6 is the y-intercept of the line. Plug this into y=\frac{3}{2} x+b as b:

y=\frac{3}{2} x-6

I hope this helps!

7 0
3 years ago
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