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grin007 [14]
3 years ago
5

Microsoft issued the Windows ME operating system. What was the impact of this 'rush to market' software product on users and Mic

rosoft's reputation?
Computers and Technology
1 answer:
Murrr4er [49]3 years ago
3 0

Answer:

The answer is below

Explanation:

Windows ME which originally meant Windows Millennium Edition. It was released in 2000. However, due to its poor functionality and efficiency, it appeared like it was rushed on the part of Microsoft to release the latest Operating System at the time. This led to some impacts on both the users and Microsoft.

1. On the Users' part: it was considered the most hated edition. Some even renamed it "Windows Mistake Edition." Users quickly dumped it for a later edition of Microsoft OS which was "Windows XP."

2. On Microsoft's part: it badly affected their reputation in the market at that period. It was the launch of Windows XP and later window 7 that revived the good reputation of Microsoft going forward.

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What are some limitations when it comes to testing and ensuring program quality? List at
DedPeter [7]

Answer:

the two limitation i can think about is the efficiency like if there are bugs or glitches or if it can get broken into and the second one is if it is running the correct program or not a lot of people deal with this problem.

Explanation: personally these are the two i can come up with at the moment

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2 years ago
Question 19
MaRussiya [10]

Answer

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Explanation:

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3 years ago
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Write a program that a C++ program that can be used to determine grades at the end of the semester. For each student, who is ide
horrorfan [7]

<u>C++ program that can be used to determine grades at the end of the semester</u>

#include <bits/stdc++.h>

using namespace std;

void func() //Defining function

{

   int m;

  double stu[60][10];

  cout<<"Enter number of students\n"; //taking input

  cin>>m;

  for(int i=0;i<m;i++)

  {

      cout<<"Enter Student Number: ";

      cin>>stu[i][0];

      cout<<"Enter the four grades of student "<<stu[i][0]<<endl;

      cin>>stu[i][1];

      cin>>stu[i][2];

      cin>>stu[i][3];

      cin>>stu[i][4];

  }

 

  //Calculating first grade average and second grade average

  for(int i=0;i<m;i++)

  {

      stu[i][5] = (stu[i][1] + stu[i][2] + stu[i][3] + stu[i][4])/4;

      stu[i][6] = (0.3*stu[i][1] + 0.2*stu[i][2] + 0.2*stu[i][3] + 0.3*stu[i][4]);

  }

  double sumFAvg=0,sumSAvg=0;

  double classFAvg,classSAvg;

  //Calculating average of first and second grades

  for(int i=0;i<m;i++)

  {

      sumFAvg = sumFAvg + stu[i][5];

      sumSAvg = sumSAvg + stu[i][6];          

  }

  classFAvg = sumFAvg/m;

  classSAvg = sumSAvg/m;

   cout<<"-----------Class Info ------------------\n";

  cout<<"StudentID   Grade1 Grade2 Grad3 Grad4 FirstGrade SecondGrade\n";

  for(int i=0;i<m;i++)

  {

      cout<<stu[i][0]<<"\t\t"<<stu[i][1]<<"\t"<<stu[i][2]<<"\t"<<stu[i][3]<<"\t"<<stu[i][4]

      <<"\t"<<stu[i][5]<<"\t"<<stu[i][6]<<endl;

  }

   cout<<"Class First Grade Average: "<<classFAvg<<endl;   //printing output

  cout<<"Class Second Grade Average: "<<classSAvg<<endl;  

 

}

int main() //driver function

{  double sumFAvg=0,sumSAvg=0;

  double classFAvg,classSAvg;

   int m;

  double stu[60][10];

   func(); //calling function

  return 0;

}

<u>Output</u>

Enter number of students 3

Enter Student Number:1 Enter the four grades of student 1-  50 60 70 80

Enter Student Number:2 Enter the four grades of student 2 -30 4 50 6

Enter Student Number:3 Enter the four grades of student 3 - 10 2 30 40

-----------Class Info ------------------

StudentID   Grade1 Grade2 Grad3 Grad4 FirstGrade SecondGrade

1  50 60 70 80 65 65

2  30 4 50 6 22.5 21.6

3  10 2 30 40 20.5 21.4

Class First Grade Average: 36

Class Second Grade Average: 36

4 0
3 years ago
Read 2 more answers
3. Write a program that inputs 4 hexadecimal digits as strings (example 7F), converts the string digits to a long – use strtol(i
never [62]

Answer:

#include <stdio.h>

#include <stdlib.h>

int main()

{

char num1[20],num2[20],num3[20],num4[20];

//Checks where the conversion of string to long stops and is required by strtol

char *ptr;

//Stores the converted number string into long.

long result_num1,result_num2,result_num3,result_num4;

//Prompt to enter all the four hexadecimal numbers.

printf("Enter the first hexadecimal number: ");

scanf("%s",num1);

printf("Enter the second hexadecimal number: ");

scanf("%s",num2);

printf("Enter the third hexadecimal number: ");

scanf("%s",num3);

printf("Enter the fourth hexadecimal number: ");

scanf("%s",num4);

//Converting the hexadecimal numbers into long using strtol() function with base 16 for hexadecimal.

result_num1 = strtol(num1,&ptr,16);

result_num2 = strtol(num2,&ptr,16);

result_num3 = strtol(num3,&ptr,16);

result_num4 = strtol(num4,&ptr,16);

//Casting the long to unsigned chars.

unsigned char numb1 = (unsigned char)result_num1;

unsigned char numb2 = (unsigned char)result_num2;

unsigned char numb3 = (unsigned char)result_num3;

unsigned char numb4 = (unsigned char)result_num4;

//Applying the boolean operation on unsigned chars and storing the resultant value in result.

unsigned char result = ((numb1&numb2)|numb3)^numb4;

//Printing the result in capital hex ("%X" take care of this).

printf("%X",result);

return 0;

}

Code OUTPUT

Enter the first hexadecimal number: 1 Enter the second hexadecimal number:2

Enter the third hexadecimal number: 3 Enter the fourth hexadecimal number: 4 Resultant Value: 7 Process returned o (0×0) execution time : 3.076 s

Press any key to continue

4 0
3 years ago
MORE FREEE POINTS AYEEE
Lerok [7]

Answer:

Hehehehehe

Explanation:

6 0
3 years ago
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