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katen-ka-za [31]
3 years ago
5

Does the data in the table represent a direct variation or an inverse variation? Write an equation to model the data in the tabl

e.
X:2,4,8,12 Y:6,3,3/2,1
Mathematics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

- Inverse Variation

- Equation: XY = 12

Step-by-step explanation:

Given

X-> 2 | 4 | 8 | 12

Y-> 6 | 3 | 3/2 | 1

Required

- State the type of variation the table represents

- Determine the equation to model the data

To check for type of variation; we'll make use of trial by error method.

To start with; We'll check for direct variation.

This is done using the following expression;

Y = kXwhere k is the constant of variation

Make k the subject of formula

k = \frac{Y}{X}

When Y = 6, X= 2

K = \frac{6}{2} = 3

When Y = 3, X = 4

K = \frac{3}{4}

There's no need to check further as both values of k are not equal

To check for inverse variation;

Y = \frac{k}{X}

Make k the subject of formula

k = YX

When Y = 6, X= 2

K = 6 * 2 = 12

When Y = 3, X = 4

K = 3 * 4 = 12

When Y = 3/2; X = 8

K = \frac{3}{2} * 8 = \frac{24}{2} = 12

When Y = 1, X = 12

K = !2 * 1 = 12

Note that for all values of X and Y, K remains constant;

Hence, the table represents an inverse direction

To determine the equation;

We make use of  k = YX

Substitute 12 for k

So, the equation becomes

12 = XY

Reorder

XY = 12

Hence, the equation is XY = 12

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The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

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