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melamori03 [73]
3 years ago
15

Factor the polymonial completely using the X method x2 + 13x - 48 quickest response gets braniliest

Mathematics
1 answer:
rusak2 [61]3 years ago
5 0

Answer:

The factored form comes from breaking each term up x2 = x times x

-48 has numerous possibilities for two factors but the two factors that multiply and get -48 while adding to get +13 are +16 and -3 so the answer in factored form is (x + 16) (x -3)

Step-by-step explanation:

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How do I solve 5x+1=7x+19
notsponge [240]

Answer:

x=-9

Step-by-step explanation:

5x+1=7x+19

1 = 7x-5x +19

1-19 = 2x

-18/2 = x

x = -9

Hope this helps!

Please mark brainliest if you think I helped! Would really appreciate!

5 0
3 years ago
The sum of two numbers is 70 and their difference is 30. Find the two numbers
ikadub [295]

Answer:

Our two numbers are 50 and 20

Step-by-step explanation:

Sum means add together

Difference means subtract each other

x + y = 70

x - y = 30

subtract from each other

2x = 100

divide both sides by 2

x = 50

our first number is 50

50 + y = 70

subtract both sides by 50

y = 20

Our two numbers are 50 and 20

8 0
3 years ago
How many significant figures will there be in the answer to the following problem? you do not have to solve the problem. 223.4 •
Irina-Kira [14]

Answer:

5 significant figures

Step-by-step explanation:

looking at the last two digit of the numbers, it multiplication gives, 4*5=20

we already have four significant figures ,

so, 2 would be the fifth since 0 is not going to be counted

3 0
3 years ago
SOLVED
Nastasia [14]
5)
a. The equation that describes the forces which act in the x-direction: 
<span>     Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span>     Fy = 200 * sin 30 </span>

<span>c. The x and y components of the force of tension: </span>
<span>    Tx = Fx = 200 * cos 30  </span>
<span>    Ty = Fy = 200 * sin 30 </span>

d.<span>Since desk does not budge, </span><span>frictional force = Fx
                                                                        = 200 * cos 30 </span>

<span>                                                 Normal force </span><span>= 50 * g - Fy
                                                                       = 50 g - 200 * sin 30 
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction: 
    (200N)cos(30) - F_s = 0

b. The equation that describes the forces which act in the y-direction:
    F_N - (200N)sin(30) - mg = 0

c. The values of friction and normal forces will be:
     Friction force= (200N)cos(30),
     
The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N

Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N
4 0
3 years ago
I need help with this asap!!! pls​
Len [333]

Answer:

ok so the answers are for all of them number 1-6 sorry

Step-by-step explanation:

1) unite rate

2) constant rate

3) proportional relationship

4) ordered pair

5) greater than

6) less than

hope this helps girlyy<33

4 0
3 years ago
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