Answer:
Doesn't have solution.
Step-by-step explanation:
x ≠ 0; x > 0 (I)
x - 5 > 0
x > 5 (II)
![log_6 x + log_6 (x + 5) = 2 \\\ log_6 [x(x + 5)] = 2 \\\ x^2 + 5x = 36 \\\ x^2 + 5x - 36 = 0 \\\ \Delta = 5^2 - 4.1.(- 36) \\\ \Delta = 169 \\\ \sqrt{\Delta} = \pm 13 \\\ x' = \frac{- 5 + 13}{2} \\\\ x' = 4 \\\ x" = \frac{- 5 - 13}{2} \\\\ x" = - 9](https://tex.z-dn.net/?f=log_6%20x%20%2B%20log_6%20%28x%20%2B%205%29%20%3D%202%20%5C%5C%5C%20log_6%20%5Bx%28x%20%2B%205%29%5D%20%3D%202%20%5C%5C%5C%20x%5E2%20%2B%205x%20%3D%2036%20%5C%5C%5C%20x%5E2%20%2B%205x%20-%2036%20%3D%200%20%5C%5C%5C%20%5CDelta%20%3D%205%5E2%20-%204.1.%28-%2036%29%20%5C%5C%5C%20%5CDelta%20%3D%20169%20%5C%5C%5C%20%5Csqrt%7B%5CDelta%7D%20%3D%20%5Cpm%2013%20%5C%5C%5C%20x%27%20%3D%20%5Cfrac%7B-%205%20%2B%2013%7D%7B2%7D%20%5C%5C%5C%5C%20x%27%20%3D%204%20%5C%5C%5C%20x%22%20%3D%20%5Cfrac%7B-%205%20-%2013%7D%7B2%7D%20%5C%5C%5C%5C%20x%22%20%3D%20-%209)
Then, this expression doesn't have solution.
I Hope I've helped you.
Answer:
1.47 times 10 to the power of -3
Step-by-step explanation:
8th grade math I'm guessing lol
See attachment for math work and answer.
Answer:
8
Step-by-step explanation:
8+12+4+3+14+1+9+13=64, 64/8=8
The one day pay is $106.25 rounded to the nearest hundredth.
<u>Step-by-step explanation:</u>
<u>From the table shown :</u>
- The timing shown in the morning is from 8:00 to 12:15
- The number of hours worked in the morning = 4 hours 15 minutes.
It is given that, the pay is $12.5 per hour.
Therefore, the pay earned in the morning = No.of hours × pay per hour.
⇒ 4 hours × 12.5 = $50
⇒ (15 mins / 60 mins) × 12.5 = $3.125
⇒ 50+3.125
⇒ 53.125
- The timing shown in the afternoon is from 8:00 to 12:15
- The number of hours worked in the morning = 4 hours 15 minutes.
Therefore, the pay earned in the afternoon = No.of hours × pay per hour.
⇒ 4 hours × 12.5 = $50
⇒ (15 mins / 60 mins) × 12.5 = $3.125
⇒ 50+3.125
⇒ 53.125
The pay for 1 day = pay earned in the morning section + pay earned in the afternoon section.
⇒ 53.125 + 53.125
⇒ 106.25
∴ The one day pay is $106.25 rounded to the nearest hundredth.