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Serga [27]
3 years ago
11

I need help with this please (sorry the picture is blurry.)

Mathematics
1 answer:
fgiga [73]3 years ago
3 0

Answer:

12:35am

Step-by-step explanation:

this is because it took 2 hours and 5 minutes for both practising and shooting. So you have to convert the 2:40pm and that will be 14:40 , the subtract the 2hours and 5mimutes from 14:40

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What is the slope of the line that passes through (8,5), (-7,20)?
Kaylis [27]
-1, because the equation for the slope is y2-y1/x2-x1. So let's bring the y value in the second set of point, which is 20, and bring the first y value in the first set of points, which is 5. 20-5 is 15. Now let's subtract the x values. So the second x from the second parentheses x value is -7, and the first x value from the first parentheses is 8. -7-8 is -15. Now we have this division equation, 15/-15, which is -1. So therefore, the slope of the line will be -1.
7 0
3 years ago
2/3x-5/4y=7 solve in standard form​
Eduardwww [97]

Answer:

8x-15y=84

Step-by-step explanation:

Multiply 12 to both sides to get rid of the fractions.

3 0
3 years ago
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What is the answer to 2h/15=20?
GarryVolchara [31]
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7 0
3 years ago
Suppose yoko borrows $3500 at an interest rate of 4% compounded each year Find the amount owed at the end of 1 year
olchik [2.2K]

Amount owed at the end of 1 year is 3640

<h3><u>Solution:</u></h3>

Given that yoko borrows $3500.

Rate of interest charged is 4% compounded each year

Need to determine amount owed at the end of 1 year.

In our case :

Borrowed Amount that is principal P = $3500

Rate of interest r = 4%

Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1

<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

A=p\left(1+\frac{r}{100}\right)^{n}

Where "p" is the principal

"r" is the rate of interest

"n" is the number of years

Substituting the values in above formula we get

\mathrm{A}=3500\left(1+\frac{4}{100}\right)^{1}

\begin{array}{l}{A=\frac{3500 \times 104}{100}} \\\\ {A=35 \times 104} \\\\ {A=3640}\end{array}

Hence amount owed at the end of 1 year is 3640

5 0
3 years ago
What happens to the value of the expression 35 + kas k decreases?
ExtremeBDS [4]

Answer:

a i think

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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