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madam [21]
2 years ago
6

URGENT HOMEWORK HELP!!

Mathematics
1 answer:
DedPeter [7]2 years ago
7 0

Answer:

A

Step-by-step explanation:

The common difference is simply the constant we add/subtract each time. In this case, the common difference is 3/2 as can be seen from the recursive formula. In other words, each new n will be 3/2 larger than the previous.

The answer is A.

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Combine like terms<br><br> 4y^2+4(7y^2-8)=<br><br> please show your work
kirza4 [7]

Answer:

32y^2-32

Step-by-step explanation:

4y^2+4(7y^2-8)

4y^2+28y^2-32

32y^2-32

if you need extra steeps explaining then plz let me know and I will help :)

8 0
3 years ago
Look at the photo<br> answers are<br> radius <br> diameter<br> center<br> circumference
Dafna1 [17]

Answer:

Diamater= D

Radius= R

Center= C

Circumference= A

Hope it Helps? :)

6 0
2 years ago
Let A(t) be the area of a circle with radius r(t), at time t in min. Suppose the radius is changing at the rate of drdt=6 ft/min
mylen [45]

Answer:

The rate of change is 108\pi ft^(2)/min

Step-by-step explanation:

The area of a circle is given by the following equation:

A(t) = \pi r^{2}

To solve this question, we have to realize the implicit differentiation in function of t. We have two variables, A and r. So

\frac{dA(t)}{dt} = 2\pi r \frac{dr}{dt}

We have that:

\frac{dr}{dt} = 6, r = 9.

We want to find \frac{dA}{dt}

So

\frac{dA(t)}{dt} = 2\pi*9*6

\frac{dA}{dt} = 108\pi

Since the area is in square feet, the rate of change is in ft^(2)/min.

So the rate of change is 108\pi ft^(2)/min

5 0
2 years ago
Help please thank you!
monitta

Answer:

• multiplied by 4p: (x -h)² +4pk = 0

• zeros for k > 0: none

• zeros for k = 0: one

• zeros for k < 0: two

Step-by-step explanation:

a) Multiplying by 4p removes the 1/(4p) factor from the squared term, but adds a factor of 4p to the k term. (It has no effect on the subsequent questions or answers, so we wonder why we're doing this.) The result is ...

(x -h)² +4pk = 0

__

b) The value of k is the vertical location of the vertex of the parabola with respect to the x-axis. The parabola opens upward, so for k > 0, the parabola does not cross the x-axis, and the number of real zeros is zero. (There are two complex zeros.)

__

c) As in part b, the value of k defines the vertex location. When it is zero, the vertex of the parabola is on the x-axis, so there is one real zero (It is considered to have multiplicity 2.)

__

d) As in part b, the value of k defines the vertex location. When it is negative, the vertex of the parabola is below the x-axis. Since the parabola opens upward, both branches will cross the x-axis, resulting in two real zeros.

_____

The attached graph shows a parabola with p=1/4 and h=2. The values shown for k are +1, 0, and -1. The coordinates of the real zeros are shown.

8 0
3 years ago
Can somebody answer this (on the picture) algebra question please
zheka24 [161]
I am torn between B and D because increased means add, but I am going to go with B 1 - 3n. I choose B because in the D option it decreases not increases. 

So the answer is B.) 1 - 3n
Hope this helps! - Alyssa

6 0
2 years ago
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