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3 years ago

First to answers gets marked brainliest

Mathematics

1 answer:

cluponka [151]3 years ago

5 0

1/2 : the probability of getting an even number when a six-sided die is rolled.

1/6 : the probability of getting a six when a six-sided die is rolled.

1/7 : the probability of randomly picking a vanilla-scented candle from a set of 3 vanilla-scented candles, 8 rose-scented candles, and 10 lavender-scented candles.

1/8 : the probability of selecting a girl named Maria to be line leader from a class of 32 girls in which 4 students are named Maria.

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How do you integrate 7xe^-5x²?

Nana76 [90]

Making assumptions about where parentheses should be,
Let u = -7x 
du = -7dx 
dv = e^(2x) dx 
v = e^(2x)/2 
∫ -7xe^(2x) dx = 
-7xe^(2x)/2 - ∫ e^(2x)/2 (-7) dx = 
-7xe^(2x)/2 + 7e^(2x)/4 + c

3 0

2 years ago

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Lubov Fominskaja [6]

Answer:

okay let's start

Step-by-step explanation:

$use \: sine \: rule \\ \frac{x}{ \sin(31) } = \frac{42}{ \sin(59) } \: \: taking \: angle \: at \: c \: as \: 90 \\ x = \frac{ 42 \sin(31)}{ \sin(59)} \\ x = 25.236146$

3 0

2 years ago

Suppose each of the following data sets is a simple random sample from some population. For each dataset, make a normal QQ plot.

adell [148]

Answer:

a) For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

b) For this case the data is skewed to the left and we can't assume that we have the normality assumption.

c) This last case the histogram is not symmetrical and the data seems to be skewed.

Step-by-step explanation:

For this case we have the following data:

(a)data = c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

We can use the following R code to get the histogram

> x1<-c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

> hist(x1,main="Histogram a)")

The result is on the first figure attached.

For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

(b)data = c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> x2<- c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> hist(x2,main="Histogram b)")

The result is on the first figure attached.

For this case the data is skewed to the left and we can't assume that we have the normality assumption.

(c)data = c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> x3<-c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> hist(x3,main="Histogram c)")

The result is on the first figure attached.

This last case the histogram is not symmetrical and the data seems to be skewed.

7 0

2 years ago

Here is the question

serg [7]

First find the amount of the difference between the original price and the current price:

$10,600 - $7,400 = $3,200

Divide the difference by the original price:

3200 / 7400 = 0.4324 = 43.2% increase.

5 0

2 years ago

What is the meaning of this WW1 quote?

Ghella [55]

The Great War (WW1) killed many empires who had been around for hundreds of years. It introduced some very inhumane weapons such as gas, and was the 1st war when old tactics met new ones. Back then, a war on this scale has never been seen.

It also gave birth to many new nations

3 0

2 years ago