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Mandarinka [93]
3 years ago
14

First to answers gets marked brainliest

Mathematics
1 answer:
cluponka [151]3 years ago
5 0

1/2 : the probability of getting an even  number when a six-sided die is  rolled.

1/6 : the probability of getting a six when a six-sided die is rolled.

1/7 :  the probability of randomly picking a vanilla-scented candle from a set of 3 vanilla-scented candles, 8 rose-scented candles,  and 10 lavender-scented candles.

1/8 : the probability of selecting a girl named Maria to be line leader from a class of 32 girls in which 4 students are named Maria.

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Which expression is equivalent to<br> 0 +<br> 2<br> 29<br> C+3<br> C+2<br> C+3<br> C+2
Kryger [21]

Answer:

C+3

Step-by-step explanation:

6 0
3 years ago
Solve the equation. <br><br><br> 12=2+z/-6
Bogdan [553]

Answer:

\boxed{\bold{z=-60}}

Step-by-step explanation:

Switch Sides

\bold{2+\frac{z}{-6}=12}

Subtract 2 From Both Sides

\bold{2+\frac{z}{-6}-2=12-2}

Simplify

\bold{\frac{z}{-6}=10}

Multiply Both Sides By -6

\bold{\frac{z\left(-6\right)}{-6}=10\left(-6\right)}

Simplify

\bold{z=-60}

3 0
3 years ago
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Find the missing side lengths. Leave your answers as radicals in simplest form
tino4ka555 [31]

We have the triangle 30° - 60° - 90°.

The lenght of the sides are in proportion: 1:2:\sqrt3\to a:2a:a\sqrt3

a=y\\2a=x\\a\sqrt3=5\\\\a\sqrt3=5\qquad\text{multiply both sides by}\ \sqrt3\\\\3a=5\sqrt3\qquad\text{divide both sides by 3}\\\\a=\dfrac{5\sqrt3}{3}\\\\2a=2\cdot\dfrac{5\sqrt3}{3}=\dfrac{10\sqrt3}{3}\\\\Answer:\ x=\dfrac{10\sqrt3}{3},\ y=\dfrac{5\sqrt3}{3}

6 0
3 years ago
Simplify: –3(y + 2)2 – 5 + 6yWhat is the simplified product in standard form?
sweet-ann [11.9K]

Answer by Mimiwhatsup:

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:2=6\\=-6\left(y+2\right)-5+6y\\-6\left(y+2\right)\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=-6,\:b=y,\:c=2\\=-6y+\left(-6\right)\cdot \:2\\Apply\:minus-plus\:rules\\+\left(-a\right)=-a\\=-6y-6\cdot \:2\\\mathrm{Multiply\:the\:numbers:}\:6\cdot \:2=12\\=-6y-12\\=-6y-12-5+6y\\\mathrm{Simplify}\:-6y-12-5+6y\\Group\:like\:terms\\=-6y+6y-12-5\\\mathrm{Add\:similar\:elements:}\:-6y+6y=0\\=-12-5\\

\mathrm{Subtract\:the\:numbers:}\:-12-5=-17\\Answer is: =-17

6 0
3 years ago
Which is the standard form of the equation of the parabola shown in the graph?
djverab [1.8K]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
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