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igor_vitrenko [27]
3 years ago
12

What is the circumference of a circle

Mathematics
1 answer:
adelina 88 [10]3 years ago
6 0

the circumference is the distance around the outside of a circle.

 If you know the radius you can use the formula

 circumference = 2 x PI x radius

 

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What is the answer to -2 2/5+3 1/4-3/5
galina1969 [7]

Answer:

1/4 or 0.25

Step-by-step explanation:

8 0
3 years ago
8640 divided by40 long division
Tju [1.3M]
The answer is 216.
https://photomath.net/s/YLLqQX
7 0
3 years ago
You are about to take the road test for your​ driver's license. You hear that only 38​% of candidates pass the test the first​ t
OLga [1]

Answer:

Answers may vary but will most likely be close to 2.

Step-by-step explanation

  1.        Given:

                 first test:38%

                 second test:76%

    SIMULATION FIRST TEST

Randomly select a 2-digit number.

If the digit is between 00 and 35 then you passed the test,else you did not pass the test.

SIMULATION SECOND TEST

Randomly select a 2-digit number.

if the digit is between 00 and 75 then you passed the test,else you did not pass the test.

SIMULATION TRIAL

Perform the simulation of the first test.if you did not pass the first test then perform the simulation of the second test.

Record the number of trials needed to pass the first or second test.

Repeat 20 times and take the average of the 20 recorded number of trials

(what is the sum of recorded values divided by 20).

Note:you will most likely obtain a result of about two trials needed.

7 0
3 years ago
Need help can someone help me
Brrunno [24]
The Cricket. because it measures 1 inch, and all the others are less that one inch.
8 0
3 years ago
The graph of f ′ (x), the derivative of f of x, is continuous for all x and consists of five line segments as shown below. Given
Rom4ik [11]

f'(x)\ge0 for all x in [-3, 0], so f(x) is non-decreasing over this interval, and in particular we know right away that its minimum value must occur at x=-3.

From the plot, it's clear that on [-3, 0] we have f'(x)=-x. So

f(x)=\displaystyle\int(-x)\,\mathrm dx=-\dfrac{x^2}2+C

for some constant C. Given that f(0)=7, we find that

7=-\dfrac{0^2}2+C\implies C=7

so that on [-3, 0] we have

f(x)=-\dfrac{x^2}2+7

and

f(-3)=\dfrac52=2.5

5 0
3 years ago
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