Answer:
Step-by-step explanation:
figure that S*** out your self jeez
Answer:
answer is C
Step-by-step explanation:
General equation of a line is expressed as shown:
y = mx+c where;
m is the slope or gradient of the line
c is the intercept of the line
Given the equation of the line graph as y =2.5x
Comparing the given equation with the general equation, it is seen that m = 2.5 and c = 0 (since there is no value for the intercept)
Based on the explanation, the y-intercept of the graph is therefore 0
Answer:
Step-by-step explanation:
7 1/7- 3 5/7= 3 3/7
3 3/7 can also be 3.42 and 24/7
Answer:
There is a 2.28% probability that it takes less than one minute to find a parking space. Since this probability is smaller than 5%, you would be surprised to find a parking space so fast.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.
Also, a probability is unusual if it is lesser than 5%. If it is unusual, it is surprising.
In this problem:
The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of 7 minutes and a standard deviation of 3 minutes, so
.
We need to find the probability that it takes less than one minute to find a parking space.
So we need to find the pvalue of Z when ![X = 1](https://tex.z-dn.net/?f=X%20%3D%201)
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{1 - 7}{3}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B1%20-%207%7D%7B3%7D)
![Z = -2](https://tex.z-dn.net/?f=Z%20%3D%20-2)
has a pvalue of 0.0228.
There is a 2.28% probability that it takes less than one minute to find a parking space. Since this probability is smaller than 5%, you would be surprised to find a parking space so fast.
Gain on retirement of bonds = book value of bond - the amount paid to the bondholders
Gain = $234,200-$227,000 = $7200.
So they will have a gain of $7200.
gain or lose= $227,000-220800= $ 7200