How do I find lateral surface area
1 answer:
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Answer:
a). 59.049°C
b). 2.1179 seconds
Step-by-step explanation:
Expression representing the final temperature after decrease in temperature of the metal from 100°C to T°C is,
T =
where x = duration of cooling
a). Temperature when x = 5 seconds
T = 100(0.9)⁵
= 59.049
≈ 59.049°C
b). If the temperature of the metal decreases from 100°C to 80°C
Which means for T = 80°C we have to calculate the duration of cooling 'x' seconds
80 =
0.8 =
By taking log on both the sides
log(0.8) =log[]
-0.09691 = x[log(0.9)]
-0.09691 = -0.045757x
x =
x = 2.1179
x ≈ 2.1179 seconds
Step-by-step explanation:
1. Amplitude = 1. g(x) = 1 sin(6x). The coefficient 1 is the amplitude. The range of the function is or, in interval notation, [-1, 1]
2. The period is .
x-intercepts (at the beginning, middle, and end of the period)
Maximum (1/4 of way through period)
Minimum (3/4 of way through period)
