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Archy [21]
3 years ago
5

Use synthetic division to determine if (x-1) is a factor of P(x) = x^4– 13x2 + 36.

Mathematics
1 answer:
arlik [135]3 years ago
3 0

Answer:

2x²+x−3 , x−1

x^{4}−2x³−10x²+7x+4, x−2

x^{4}−2x³−10x²+7x+4, x−1

Step-by-step explanation:

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Among all right triangles whose hypotenuse has a length of 12 cm, what is the largest possible perimeter?
Veronika [31]

Answer:

Largest perimeter of the triangle =  

P(6\sqrt{2}) = 6\sqrt{2} + \sqrt{144-72} + 12 = 12\sqrt{2} + 12 = 12(\sqrt2 + 1)

Step-by-step explanation:

We are given the following information in the question:

Right triangles whose hypotenuse has a length of 12 cm.

Let x and y be the other two sides of the triangle.

Then, by Pythagoras theorem:

x^2 + y^2 = (12)^2 = 144\\y^2 = 144-x^2\\y = \sqrt{144-x^2}

Perimeter of Triangle = Side 1 + Side 2 + Hypotenuse.

P(x) = x + \sqrt{144-x^2} + 12

where P(x) is a function of the perimeter of the triangle.

First, we differentiate P(x) with respect to x, to get,

\frac{d(P(x))}{dx} = \frac{d(x + \sqrt{144-x^2} + 12)}{dx} = 1-\displaystyle\frac{x}{\sqrt{144-x^2}}

Equating the first derivative to zero, we get,

\frac{dP(x))}{dx} = 0\\\\1-\displaystyle\frac{x}{\sqrt{144-x^2}} = 0

Solving, we get,

1-\displaystyle\frac{x}{\sqrt{144-x^2}} = 0\\\\x = \sqrt{144-x^2}}\\\\x^2 = 144-x^2\\\\x = \sqrt{72} = 6\sqrt{2}

Again differentiation P(x), with respect to x, using the quotient rule of differentiation.

\frac{d^2(P(x))}{dx^2} = \displaystyle\frac{-(144-x^2)^{\frac{3}{2}}-x^2}{(144-x)^{\frac{3}{2}}}

At x = 6\sqrt{2},

\frac{d^2(V(x))}{dx^2} < 0

Then, by double derivative test, the maxima occurs at x = 6\sqrt{2}

Thus, maxima occurs at x = 6\sqrt{2} for P(x).

Thus, largest perimeter of the triangle =  

P(6\sqrt{2}) = 6\sqrt{2} + \sqrt{144-72} + 12 = 12\sqrt{2} + 12 = 12(\sqrt2 + 1)

7 0
3 years ago
What is the difference between divergence and convergence testing outliers?
LuckyWell [14K]
A divergence testing just diverts your mind and imagination into several possibilities and scenarios regarding the same issue.
A divergence test will simply test your imagination and forces your mind  to go into as many directions as possible.

On the other hand, a converge test will sort of converge your imagination and your mind into a set of possibilities or options.
A convergence test will let you sort between a set of possibilities and decide on the best one.
8 0
3 years ago
DESPERATELY NEED HELP.GEOMETRY REFLECTIONS/ COMPOSITIONS. Provide an explanation if possible. Thank you
DedPeter [7]
Subtract 7 from 4 and Mark it on the grid, then, in order to reflect it, mark the same line in the (-,+) corner. (new coordinates are (-5,7)(-5,3)
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3 years ago
What is the length of line segment XZ
algol13
8 units that Is the answer
4 0
3 years ago
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Onny wants to buy a guitar that costs $600. He makes $2 per day. How many days will it take Onny to save enough money to buy the
lana66690 [7]

Answer:

300 days

Step-by-step explanation:

What you have to do is divide 600/2. Then you get 300.

Hope it helped :)

4 0
3 years ago
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