The equation of the plane are-
- In cartesian form; 8x + 3y + 4z = 62
- In vector form; r(8i + 3j + 4z ) = 62
<h3>What is plane in 3-Dimension plane?</h3>
A three dimensional plane or 3d plane contains three axes which intersect at the origin. The three axes, namely x-axis, y-axis and z-axis are mutually perpendicular to each other. Thus, a 3d plane is called a hyperplane. The points in the 3d plane are of the form (x, y, z).
According to the question.
The plane through the point (5, 2, 4).
The normal vector 8i + 3j + 4k
Equation of plane traveling through a given position vector and having the specified normal vector is expressed as:
8(x-5) + 3(y-2) + 4(z-4) =0
8x - 40 + 3y - 6 + 4z - 16 = 0
8x + 3y + 4z - 62 = 0
8x + 3y + 4z = 62 ( equation of the plane in cartesian form)
Equation of plane in vector form is;
r(8i + 3j + 4z ) = 62
To know more about the 3-Dimension plane, here
brainly.com/question/7150882
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