Answer:
3 in
Step-by-step explanation:
The volume of the large sphere is ...
V = (4/3)πr³ = 288π . . . cubic inches
The volume of the smaller sphere is ...
288π -252π = 36π . . . cubic inches
The ratio of volumes of the smaller sphere to the larger is the cube of the ratio of radii. The radius of the smaller sphere will be ...
(6 in)∛(36π/(288π)) = (6 in)∛(1/8) = 3 in . . . . small sphere radius
Answer:
-18
Step-by-step explanation:
x=2 so,
-9(2) = -18
hope this helps
Answer:
The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = 0.00621
Step-by-step explanation:
This is a normal distribution problem
The mean of the sample = The population mean
μₓ = μ = 4 ounces
But the standard deviation of the sample is related to the standard deviation of the population through the relation
σₓ = σ/√n
where n = Sample size = 100
σₓ = 1.2/√100
σₓ = 0.12
The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3)
To do this, we first normalize/standardize the 4.3 ounces
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ = (4.3 - 4)/0.12 = 2.5
To determine the probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = P(z > 2.5)
We'll use data from the normal probability table for these probabilities
P(x > 4.3) = P(z > 2.5) = 1 - P(z ≤ 2.5) = 1 - 0.99379 = 0.00621
M A T H W A Y always helps. its without the spaces lol
