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Svet_ta [14]
3 years ago
11

2x²+5=13 How do you find the value of x?

Mathematics
2 answers:
anzhelika [568]3 years ago
7 0
Since 5<span> does not contain the </span>variable<span> to solve for, move it to the right-hand side of the </span>equation<span> by subtracting </span>5<span> from both sides.
</span>2<span>x^2</span>=−5+<span>13
</span>
Add <span>−5</span><span> and </span>13<span> to get </span><span>8.
</span><span>2<span>x^2</span>=8

</span>Divide<span> each </span>term<span> in the </span>equation<span> by </span><span>2.
</span><span><span>x^2</span>=4

</span>Take the square root<span> of both sides of the </span>equation<span> to </span>eliminate<span> the </span>exponent<span> on the left-hand side.
</span><span>x=±</span>√4

Rewrite 4 as <span>2^2
</span><span>x=±</span>√<span><span>2^2</span>
</span>
Pull terms<span> out from under the </span>radical<span>.
</span><span>x=±2
</span>
First, use the positive value of the ±<span> to find the first </span>solution<span>.
</span><span>x=2
</span>
Next, use the negative value of the ±<span> to find the </span>second solution<span>.
</span><span>x=−2


</span><span>x=2,−2</span>
vladimir1956 [14]3 years ago
5 0
2x²+5=13
subtract the 5 on both sides
2x²=8
divide by 2 on both sides
x²=4
put each side under the radical because of the exponent 2
√x²=√4
the radical cancels out the exponent 2; √4 = 2
x=2
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lbvjy [14]

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How can I solve this question???
eduard

Answer:

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step 1

Find the measure of the central angle of the regular pentagon

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