Answer:
See explanation below.
Step-by-step explanation:
The prime numbers are bold:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
18 19 20 21 22 23 24 25 26 27 28 29 30 31
a) We can see that as we go higher, twin primes seem less frequent but even considering that, there is an infinite number of twin primes. If you go high enough you will still eventually find a prime that is separated from the next prime number by just one composite number.
b) I think it's interesting the amount of time that has been devoted to prove this conjecture and the amount of mathematicians who have been involved in this. One of the most interesting facts was that in 2004 a purported proof (by R. F. Arenstorf) of the conjecture was published but a serious error was found on it so the conjecture remains open.
Answer:hmm I think point d
I’m not to sure ✨
Step-by-step explanation:
Answer:
The first rocket, g(x), reached its maximum height before the second rocket, h(x).
Step-by-step explanation:
Each equation is in vertex form, so we can read the vertex of the rocket's path from the equation.
y = a(x -h)^2 +k . . . . . . has vertex (h, k)
__
g(x) has vertex (time, max height) = (4, 170).
h(x) has vertex (time, max height) = (5, 170).
The rockets have the same maximum height (170), but the first rocket, g(x), reaches that height in 4 seconds, one second sooner than the second rocket, h(x).
The first rocket, g(x), reached its maximum height before the second rocket, h(x).
Answer:
7f
r = ----------- - 4
z
Step-by-step explanation:
I will assume that you meant:
7f
z = ------------
r + 4
Solve for r. Start by interchanging z and (r + 4):
7f
r + 4 = -----------
z
Now subtract 4 from both sides. This isolates r:
7f
r = ----------- - 4
z
All you have to do is find (3/10) of 60, and find the triangle with that number
for its label.
The exact same kind of problem was answered correctly by 2 people for the question you posted 9 minutes earlier, and one of them even explained how
he did it. If you're getting anything more than answers from Brainly ... I mean
if you're actually getting HELP here ... then you ought to be able to answer
this one on your own.
