Question

If f(x) = 4x + 3 and g(x) = 3x, evaluate for X = -1/2

Answer 1

Answer:

 $f(-\frac{1}{2}) = 1$

$g(-\frac{1}{2} ) = -\frac{3}{2}$

Step-by-step explanation:

Given the function $f(x) = 4x + 3$ and the function $g(x) = 3x$, to evaluate for $x=-\frac{1}{2}$, you need to substitute it into each function.

Then, for the function f(x), when  $x=-\frac{1}{2}$, you get:

 $f(-\frac{1}{2}) = 4(-\frac{1}{2}) + 3$

 $f(-\frac{1}{2}) = 4(-\frac{1}{2}) + 3$

 $f(-\frac{1}{2}) = -\frac{4}{2}+ 3$

 $f(-\frac{1}{2}) = -2 + 3$

 $f(-\frac{1}{2}) = 1$

For the function g(x), when  $x=-\frac{1}{2}$, you get:

$g(-\frac{1}{2} ) = 3(-\frac{1}{2})$

 $g(-\frac{1}{2} ) = -\frac{3}{2}$

Answer 2

Answer:

f(-1/2) = 1

g(-1/2) =-3/2

Step-by-step explanation:

f(x) = 4x+3

Let x = -1/2

f(-1/2) = 4(-1/2) +3

f(-1/2) = -2 +3

f(-1/2) =1

g(-1/2) = 3(-1/2)

          = -3/2