Answer:
![x(\sqrt[12]{x^5} )](https://tex.z-dn.net/?f=x%28%5Csqrt%5B12%5D%7Bx%5E5%7D%20%29)
Step-by-step explanation:
We need to remember 2 rules when doing these:
1. ![\sqrt[n]{x^a} =x^{\frac{a}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ea%7D%20%3Dx%5E%7B%5Cfrac%7Ba%7D%7Bn%7D%7D)
2. 
Using these 2 rules, we can simplify the product (steps shown below):
![\sqrt[3]{x^2} *\sqrt[4]{x^3} \\=x^{\frac{2}{3}}*x^{\frac{3}{4}}\\=x^{\frac{2}{3}+\frac{3}{4}}\\=x^{\frac{17}{12}}\\=x^{\frac{12}{12}+\frac{5}{12}}\\=x(x^{\frac{5}{12}})\\=x(\sqrt[12]{x^5} )](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D%20%2A%5Csqrt%5B4%5D%7Bx%5E3%7D%20%5C%5C%3Dx%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%2Ax%5E%7B%5Cfrac%7B3%7D%7B4%7D%7D%5C%5C%3Dx%5E%7B%5Cfrac%7B2%7D%7B3%7D%2B%5Cfrac%7B3%7D%7B4%7D%7D%5C%5C%3Dx%5E%7B%5Cfrac%7B17%7D%7B12%7D%7D%5C%5C%3Dx%5E%7B%5Cfrac%7B12%7D%7B12%7D%2B%5Cfrac%7B5%7D%7B12%7D%7D%5C%5C%3Dx%28x%5E%7B%5Cfrac%7B5%7D%7B12%7D%7D%29%5C%5C%3Dx%28%5Csqrt%5B12%5D%7Bx%5E5%7D%20%29)
Rearranging, we see that it is the third choice.
You have to divide and 512/14=36 and 8/14 and that simplified is 36 and 4/7.
Answer:
2. a and b only.
Step-by-step explanation:
We can check all of the given conditions to see which is true and which false.
a. f(c)=0 for some c in (-2,2).
According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.
b. the graph of f(-x)+x crosses the x-axis on (-2,2)
Let's test this condition, we will substitute x for the given values on the interval so we get:
f(-(-2))+(-2)
f(2)-2
-1-1=-3 lower limit
f(-2)+2
1+2=3 higher limit
according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.
c. f(c)<1 for all c in (-2,2)
even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.
The final answer is then 2. a and b only.
Answer:
b=1
Step-by-step explanation:
6*1=6
6*8=48
Answer:
6x-3
Step-by-step explanation:
