Answer:
if I'm not mistaken your answer is 1
Answer:
maximum height is 80 feet
8 seconds until it hits ground
Step-by-step explanation:
-5t(t - 8) = 0
-5t= 0; t = 0 (this represents the beginning of the throw)
t-8=0; t = 8 (this represents the end of the throw)
To find maximum height, find the vertex of the graph,
you can use -b/2a to find 't' and then substitute that value back into the function to find h(t)
x = -40÷2(-5)
x = -40/-10
x = 4
h(4) = -5(4²)+40(4)
h(4) = -5(16) + 160 which is 160 - 80 = 80
