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telo118 [61]
3 years ago
7

Please help algebra II

Mathematics
1 answer:
malfutka [58]3 years ago
7 0

Answer:

yes its a function

Step-by-step explanation:

A function is a problem that has an x value used only once. in this problem you provided, it goes horizontal across the x axis so no x value will be used twice.

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write the equation of the line that is parallel to y = 4x -7 and passes through the point (-2, -5). show your work.​
natita [175]

Answer:

y = 4x + 3

Step-by-step explanation:

To do this, put the new line into the form y = mx + b where m is the slope and b is the y-intercept.

When two lines are parallel, they have the same slope. Since, the slope of the first line is 4, that means the slope of the second line is also 4.

So far, the equation is y = 4x + b.

Then, since you know (-2, -5) is a solution, x = -2, y = -5 is a solution so you can plug this into the equation.

This would be:

-5 = 4 * -2 + b

-5 = -8 + b

3 = b

This means the equation is y = 4x + 3.

7 0
3 years ago
There are a total of 84 green cars, 35 blue cars, and 42 red cars parked in the parking lot. How many cars are parked in the par
Cloud [144]
Ok so you just have to add all of the quantities together so 84+35=119 and then 119+42=161 so there are 161 cars in the parking lot. Hope this helps
8 0
4 years ago
Read 2 more answers
What is the prime factorization of 45?<br> A 23 x 5<br> 32 x 5<br> 52 X 3<br> 52 X 9
Ksivusya [100]

Answer:45=3x3x5

Step-by-step explanation:

prime factorization of 45

45 ➗ 3=15

15 ➗ 3=5

5 ➗ 5=1

45=3x3x5

5 0
3 years ago
a falling stone is at a certain instant 230 feet above the ground. 3 seconds later it is only 14 feet above. From what height wa
vazorg [7]
The falling stone is a certain instant 230 feet above the ground. 3 seconds later it is only 14 feet above. The height that it was dropped is 32 feet. The equation for the answer is; 

<span>16<span>t2</span>+<span>h0</span>=230</span> <span>−16(t+3<span>)2</span>+<span>h0</span>=14</span>


4 0
3 years ago
Read 2 more answers
Explain the special pattern for sketching a parabola
Lady bird [3.3K]

Answer:

the parabola can be written as:

f(x) = y = a*x^2 + b*x + c

first step.

find the vertex at:

x  = -b/2a

the vertex will be the point (-b/2a, f(-b/2a))

now, if a is positive, then the arms of the parabola go up, if a is negative, the arms of the parabola go down.

The next step is to see if we have real roots by using the Bhaskara's equation:

x =  \frac{-b +-\sqrt{b^2 -4ac} }{2a}

Now, draw the vertex, after that draw the values of the roots in the x-axis, and now conect the points with the general draw of the parabola.

If you do not have any real roots, you can feed into the parabola some different values of x around the vertex

for example at:

x =  (-b/2a) + 1 and x =  (-b/2a) - 1

those two values should give the same value of y, and now you can connect the vertex with those two points.

If you want a more exact drawing, you can add more points (like x =  (-b/2a) + 3 and x =  (-b/2a) - 3) and connect them, as more points you add, the best sketch you will have.

8 0
3 years ago
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