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Kay [80]
3 years ago
11

Suppose you add or subtract two quadratic trinomials that use the same variable. What are the possible classifications for the s

um or difference? Explain.
Please help me asap. T.T
Mathematics
1 answer:
Leno4ka [110]3 years ago
3 0

Answer:

quadratic monomial, quadratic trinomial, constant monomial, linear monomial, quadratic binomial, linear binomial.

Step-by-step explanation:

two quadratic trinomials each have a degree-2, degree-1, and degree-0 term. It is possible that the coefficients of all or some of the terms cancel each other while adding or subtracting the polynomials.

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Please Help!!
algol13
When you see questions of this nature, test the individual inequalities and look out for their intersection.

For
y < \frac{2}{3} x
Choose a point in the lower or upper half plane created by the line
y = \frac{2}{3} x
The above line is the one which goes through the origin.

Now testing (1,0) yields,

0 < \frac{2}{3} (1)
That is,

0 < \frac{2}{3}
This statement is true. So we shade the lower half of
y = \frac{2}{3} x

For
y \geqslant - x + 2
We test for the origin because, it is not passing through the origin.

0 \geqslant - (0) + 2
This yields
0 \geqslant 2
This statement is false so we shade the upper half.

The intersection is the region shaded in B. The top right graph
8 0
3 years ago
What is HCF and LCM ? # confused
GaryK [48]
HCF= highest common factor
LCM= least common multiple
7 0
3 years ago
Read 2 more answers
(i) 809, 708, 607, _____, _ class 4<br>__class 4​
schepotkina [342]

Answer:

809, 708, 607, 506, 405, 304, 203, 102, 1, -100

Step-by-step explanation:

809, 708, 607, _____, _______

First term = 809

Second term = 708

Third term = 607

Difference between first term and second term = 809 - 708

= 101

Difference between second term and third term = 708 - 607

= 101

Therefore, the common difference is 101

Fourth term = 607 - 101

= 506

Fifth term = 506 - 101

= 405

Sixth term = 405 - 101

= 304

Seventh term = 304 - 101

= 203

Eighth term = 203 - 101

= 102

Ninth term = 102 - 101

= 1

Tenth term = 1 - 101

= - 100

809, 708, 607, 506, 405, 304, 203, 102, 1, -100

4 0
2 years ago
Which properties justify the steps taken to solve the system? {3x−2y=10 4x−3y=14
Alexeev081 [22]
The answer is: Substitution property of equality.

 The explanation is shown below:

1. To solve this problem you must apply the proccedure shown below:

 2. When you clear the variable x from the first equation, and subtitute it into the second equation, you obtain:

 <span>3x−2y=10
 x=(10+2y)/3

 4x−3y=14
 </span>4[(10+2y)/]−3y=14
<span> y=-2

 3. When you subsitute y=-2 into the first equation and clear the x, you have:

 x=2
 </span>
7 0
3 years ago
Read 2 more answers
Who is the person in the end of intergalctic?
andrew11 [14]
Its lil turbo and mr beef cKE

6 0
3 years ago
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