Answer:
t=6
Step-by-step explanation:
ground height = 0
(are you sure your formula is correct? isn't it - 16t²?)
if h=16t² +64t+192 is true then
16t² +64t+192 = 0
t² + 4t + 12 = 0
t = (-4 ± √(4² - 4*12)) / 2*1 = (-4 ± √-32) / 2 = -2 ± 2√-2
There is no solution of t
if it is h= - 16t² +64t+192
0 =- 16t² + 64t + 192
t² - 4t - 12 = 0
(t + 2) (t -6) = 0
t should be positive
t = 6 sec
You need to go from slope-intercept (
) to standard form (
).
slope-intercept form of your provided values:
now, solve for x and y
Your answer is .
Answer:
The most reasonable answer would likely be the first.
"When a pair of parallel lines is intersected by a third line, the alternate exterior angles are congruent."
Step-by-step explanation:
Answer:
602
Step-by-step explanation:
Answer:
2nd one
Step-by-step explanation:
