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LUCKY_DIMON [66]
3 years ago
10

"Find the missing side Lengths. Leave your awnser as radicals in simple form"

Mathematics
1 answer:
iren2701 [21]3 years ago
8 0

Answer:

Step-by-step explanation:

5) x = 6sin45 = 6(√2)/2 = 3√2

   y = 6cos45 = 6(√2)/2 = 3√2

6) x = 2√6sin45 = 2√6(√2)/2 = 2√3

   y = 2√6cos45 = 2√6(√2)/2 = 2√3

7) x = 16sin60 = 16(√3)/2 = 8√

   y = 16cos60 = 16(½) = 8

8) u = 2/sin30 = 2 / ½ = 4

   v = 2/tan30 = 2/(1 /√3) = 2√3

Please select as brainliest if it fits.

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Can someone please give me a good explanation of how to work this out! 15 points for a good answer.
Leya [2.2K]
  • Answer:

<em>= 26,(6)</em>

<em>≈ 26,7</em>

  • Step-by-step explanation:

<em>C = 5/9(F - 32)</em>

<em>= 5/9(80 - 32)</em>

<em>= 5/9(48)</em>

<em>= 5×48/9</em>

<em>= 240/9</em>

<em>= 26,(6)</em>

<em>≈ 26,7</em>

7 0
3 years ago
Read 2 more answers
Two-fifths of a number is decreased by three. Find the value of the expression if the number is twenty-five.
Sindrei [870]
Let's take the number as x.

two-fifths of a number = 2x / 5
decreased by 3 = (2x/5) - 3

(2x/5) - 3
(2*25/5) - 3
(2*5) - 3
10 - 3
7 
8 0
4 years ago
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Simplify. Type your answer in the space provided. Do not include spaces in your answer. Answer in terms of an 2 improper fractio
Aleksandr-060686 [28]

Answer:

can't see

Step-by-step explanation:

7 0
4 years ago
The mass of the particles that a river can transport is proportional to the fifth power of the speed of the river. A certain riv
vlada-n [284]

Answer: V = 5.22m/s

Step-by-step explanation:

Given that the mass of the particles is proportional to the fifth power of the speed. That is

M = k V^5

Where M = mass and V = speed

K = constant of proportionality

A certain river normally flows at a speed of 3 miles per hour

V = 3 mph

M = unknown

M = k × 3^5

M = 243K

K = M/243 ........(1)

What must its speed be in order to transport particles that are 16 times as massive as usual

M = 16M

Using same formula

I.e M = KV^5

16M = M/243 × V^5

M will cancel out

16 = V^5/243

V^5 = 3888

V = 5.22m/s

5 0
4 years ago
What is the radical form of each of the given expressions?
Ahat [919]

Answer:

Step-by-step explanation:

These exponential forms can be written into radicals very easily as long as you remember the rule:  The denominator of the rational exponent serves as the index of the radical and the numerator serves as the exponent on the radicand. Let's look at a rational exponent.  3/4  4 would be the index on the radical (the number that sits in the little dip of the radical sign) and 3 is the power on the base.  So

x^{\frac{3}{4}} can be written in radical form as

\sqrt[4]{x^3}

Let's do 3^3/2 in your problem.  2 is the index (which is a "normal" square root and you don't need to write a 2 there cuz it's understood that it's a 2 if nothing is there), and 3 is the power on the base, which in our case is a 3.  Bases can be numbers OR letters.

3^{\frac{3}{2}}=\sqrt[2]{3^3}=\sqrt{3^3}

That does in fact have an actual number answer, but I don't think you are simplifying them yet, only learning to write them from one form to another, so there you go!

5 0
3 years ago
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