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3 years ago

Find X. This is a 40°, 40°, 90° triangle.

Mathematics

1 answer:

sergiy2304 [10]3 years ago

6 0

Answer:

In a 45°−45°−90° triangle, the length of the hypotenuse is √2 times the length of a leg. To see why this is so, note that by the Converse of the Pythagorean Theorem , these values make the triangle a right triangle. Note that an isosceles right triangle must be a 45°−45°−90° triangle.

Step-by-step explanation:

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Kobotan [32]

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translate to English please thanks!

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3 years ago

Which of the following ordered pairs is a solution of 2x-y=-9?

Ann [662]

Answer:

(4,-1)

Step-by-step explanation:

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3 years ago

Read 2 more answers

PROVE :<br><br>sin^2(-300°).cos^2 (120)+ cos^2(-240 ).sin^2(390)=1/4

leva [86]

Step-by-step explanation:

$\sin {}^{2} ( - 300) \cos {}^{2} (120) + \cos {}^{2} ( - 240) \sin {}^{2} (390) = \frac{1}{4}$

$\sin {}^{2} (60) \cos {}^{2} ( {}^{} 120) + \cos {}^{2} (120) \sin {}^{2} (30)$

$\frac{3}{4} \frac{1}{4} + \frac{1}{4} \frac{1}{4}$

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2 years ago

Ricky says (x5)(x3) = x15 Rocky says (x5)(x) = x ? Who is correct? Why?

atroni [7]

Answer:

1.rocky

Step-by-step explanation

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3 years ago

In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta

Advocard [28]

Answer:

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.3246

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.3646\frac{0.06}{\sqrt{8}} = 0.0502$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

8 0

3 years ago