First let us find the length of JN
JN =JK +KN
JN = 82+105 = 187
JN=187..............(1)
UC= JN -( JH +HU+CN)
We are given :
JH= 22, HU = 96 and CN = 51
plugging all the values we get
UC = 187-( 22+96+51)
UC =187 -169
UC = 18
Answer is UC =18 ( option B)
I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have
C(8,3) = 8!/(8-3)!3!
C(8,3) = 56
There are 56 3-person teams that can be formed from the 8 students.
Answer:
$162 to make a 35% profit
Step-by-step explanation:
35% of 120 is 42. Add the 42 to 120.
Answer: The numbers are decreasing by 2. So that means that the eighteenth number would be -29.
Explanation:
{5, 3, 1, -1, -3, -5, -7, -9, -11, -13, -15, -17, -19, -21, -23, -25, -27, -29...}
Answer:
d
Step-by-step explanation:
Solution by substitution method
y=7x+8
∴y-7x=8
and y=x+20
∴y-x=20
Suppose,
-7x+y=8→(1)
and -x+y=20→(2)
Taking equation (1), we have
-7x+y=8
⇒y=7x+8→(3)
Putting y=7x+8 in equation (2), we get
-x + 7x + 8 = 20
6x = 20-8
6x = 12
x= 12 / 6
x = 2
substitute for x in equation (3)
y = 7(x) + 8
y = 7(2) + 8
y = 22
