I’ll give you brainliest, please help!

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

Circumference and area of a circle help me please

Free_Kalibri [48]

A.) The circumference of the tire is 94.2

B.) The tire will have to rotate 56 times to
travel 1 mile.

3 0

2 years ago

1. Let’s see how many different routes there are to some of your favorite places. Remember, you always take the shortest path!

OleMash [197]

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7 0

3 years ago

Find the sum or difference (2c-4)+(5c+11)

laiz [17]

Remove parentheses
2c - 4 + 5c + 11
Combine like terms
Answer: 7c + 7

7 0

3 years ago

Assume that 2 cards are drawn from a standard 52-card deck. Find the following probabilities.

topjm [15]

Answer:

Step-by-step explanation:

WITHOUT replacement of first card drawn:

P(a 10 is drawn) = 13/52 = 1/4

P(the next draw is a 10) = 12/52 = 3/13

P(drawing two 10s without replacement of the first draw) = (1/4)(3/13) = 3/52

WITH replacement of first card:

P(two 10s are drawn) = P(first card is a 10)*P(first card is a 10) = (4/13)(4/13) =

16/169

7 0

3 years ago