Answer:
The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 230 - 3.99 = 226.01
The upper end of the interval is the sample mean added to M. So it is 230 + 3.99 = 233.99.
The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.
It's looking for the measures
m<F + m<G = 180°
(4x)° + (8x)° = 180°
12x = 180°
÷12 ÷12
x = 15
check your work
m<F + m<G = 180°
(4x)° + (8x)° = 180°
4(15)° + 8(15)° = 180°
60° + 120° = 180°
The intervals on which the graph is increasing: ]-∞,-3[ U ]0.5,-∞[ . On the other hand, the graph is decreasing: ]-3,0.5[
<h3>Function</h3>
A function can be classified as increasing or decreasing. Thus, a function is increasing when the y-values increase, on the other hand, a function is decreasing when the y-values decrease.
From the image, you can see that the y-values increase in the following x-intervals: from -∞ to -3 and from 0.5 to ∞. Using interval notation, you can write that the function is increasing in:
]-∞,-3[ U ]0.5,-∞[
From the graph, you can see that the y-values decrease in the following x-intervals: from -3 to 0.5. Using interval notation, you can write that the function is decreasing in:
]-3,0.5[
Learn more about function here:
brainly.com/question/2649645
Step-by-step explanation:
The volume of the cone is:
1/3 *π* r² *h =
1/3 *π *4* 2square root of 3=
(8*square root of 3*π)/3
Answer:
c. (x + 3)
Step-by-step explanation:
using factor theorem
if x - 3 is a factor then p(a) = 0
p(a)= x^3 - 3x^2 - 4x + 12
a.(x-3)
p(3) = (3)^3 - 3(3)^2 - 4(3) + 12
= 27 - 27 - 12 + 12
= 0
therefore x-3 is a factor
b.(x + 2)
p(-2) = (-2)^3 - 3(-2)^2 - 4(-2) + 12
= -8 -12 + 8 + 12
,= 0
therefore x + 2 is a factor
c.(x + 3)
p(-3) = (-3)^3 - 3(-3)^2 - 4(-3) + 12
= -27 -27 + 12 + 12
= -30
therefore x + 3 is not a factor
d.(x-2)
p(2) = (2)^3 - 3(2)^2 - 4(2) + 12
= 8 -12 - 8 + 12
= 0
therefore x - 2 is a factor
