$3000 x .04 =$120
$120 x 10 =$1200
$3000+1200= $4200 Total
2y² + y - 3
(2y+3)(y-1)
2y(y-1) + 3(y-1)
2y² - 2y + 3y - 3
2y² + y - 3
2y + 3 = 0
2y = -3
y = -3/2
y = -1 1/2
y - 1 = 0
y = 1
2y² + y - 3 = 0
2(-3/2)² + (-3/2) - 3 = 0
2(9/4) - 3/2 - 3 = 0
18/4 - 3/2 - 3 = 0
18/4 - (3/2 * 2/2) - 3(4/4) = 0
18/4 - 6/4 - 12/4 = 0
(18 - 6 - 12)/4 = 0
(18 -18)/4 = 0
0/4 = 0
0 = 0
Answer:


Step-by-step explanation:
Given


Required
x and y
Add both equations to eliminate y


Divide both sides by 6

Substitute
in the first equation





Divide by -3

The value of the coefficient B will be 9.
<h3>What will be the value of B in equation written below?</h3>
2(x+By)(x-2y)
=2(x^2 -2xy +Bxy -2By^2)
=2x^2 -4xy + 2Bxy - 4By^2
The original form is 

hence the value of B=9
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