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IRISSAK [1]
3 years ago
7

in the first quadrant you start at 11,8 and move 9 units left and 3 units up what point will you end up on

Mathematics
1 answer:
Umnica [9.8K]3 years ago
8 0
Eleven subtract nine is two; eight adding three is eleven (2,11)
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Sup guys i was wondering if i could get some help
love history [14]
0=x3-3x2
x3-3x2=0
x2•(x-3)=0
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8 0
3 years ago
If 5/8 of the people in water aerobics class are over age 65 and 1/4 of the people in the class are under age 40,what fraction o
LiRa [457]
I think the answer's 7/8. If you convert 1/4 to 2/8 and add them together, you add 5/8 and 2/8 to get 7/8. 
6 0
3 years ago
Simplify the following expression. 12a + 2a
mamaluj [8]

Answer:

14a

Step-by-step explanation:

Combining like-terms gives us 12a+2a=14a

Hope this helped!

6 0
2 years ago
Read 2 more answers
What are the distinct factors of 75
Lelechka [254]
The factors and 75 is 175 and 25 and three and five and 30
3 0
3 years ago
When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected
jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

N=\frac{12.36}{0.03+0.55^t}

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

N=\frac{12.36}{0.33+0.55^0}

N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12

A. Initially, there were 12 deer.

B. N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

8 0
3 years ago
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