The equation for finding the area of a triangle is (bh)/2.
(The slash is a division sign)
So, with this equation, it would be (19*12)/2.
That would equal 114. So the answer is 114 ft squared.
Answer:
![6^{\frac{1}{5} }=\sqrt[5]{6}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B1%7D%7B5%7D%20%7D%3D%5Csqrt%5B5%5D%7B6%7D)
![6^{\frac{7}{5} }=\sqrt[5]{6^7}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B7%7D%7B5%7D%20%7D%3D%5Csqrt%5B5%5D%7B6%5E7%7D)
![6^{\frac{1}{6} }=\sqrt[6]{6}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B1%7D%7B6%7D%20%7D%3D%5Csqrt%5B6%5D%7B6%7D)
![7^{\frac{1}{2} }=\sqrt[2]{7}](https://tex.z-dn.net/?f=7%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%3D%5Csqrt%5B2%5D%7B7%7D)
![7^{\frac{5}{2} }=\sqrt[2]{7^5}](https://tex.z-dn.net/?f=7%5E%7B%5Cfrac%7B5%7D%7B2%7D%20%7D%3D%5Csqrt%5B2%5D%7B7%5E5%7D)
![6^{\frac{9}{2} }=\sqrt[2]{6^9}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B9%7D%7B2%7D%20%7D%3D%5Csqrt%5B2%5D%7B6%5E9%7D)
Step-by-step explanation:
A radical is the root operation for n roots such as square root or cuberoot in the form ![\sqrt[n]{x}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D)
. A fraction exponent 
can be converted to the radical form.
I found the picture of the bowl.
AB is the diameter of the sphere.
So the radius is 20in / 2 = 10 in
And the volume of water is half the volume of the sphere.
=> V of water = (1/2)* (4/3) π (r^3)
Also, this problems asks to use 22/7 as approximation of π.
=> V of water = (1/2) (4/3) (22/7) (10in)^3 = 2,095 in^3
Answer: (1/2)(4/3)(22/7)(10in)^3 = 2,095 in^3
Due the parentheses first so 16+4+11*2-21 then multiply 16+4+22-21 from here you can answer left to right 20+4+22-21 then 24+1=25
