If contact lenses cost 80$ how much will they cost if they are with 10% off?

Graph quadrilateral abcd whose vertex matrix is shown below. Then graph the dilation of quadrilateral abcd with a scale factor o

makkiz [27]

Answer:

The answer is below

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation is reflection, translation, rotation and dilation.

Dilation is the increase or decrease in size of an object.

Given the vertex matrix of quadrilateral ABCD as:

$\left[\begin{array}{cccc}-1&5&5&-4\\2&5&3&-1\end{array}\right]$

Therefore the vertex of quadrilateral ABCD is at A(-1, 2), B(5, 5), C(5, 3) and D(-4, -1).

Quadrilateral ABCD is dilated by a scale factor of 3 to produce quadrilateral A'B'C'D'.

Hence, the vertex matrix of quadrilateral A'B'C'D' is:

$3\left[\begin{array}{cccc}-1&5&5&-4\\2&5&3&-1\end{array}\right]=\left[\begin{array}{cccc}-3&15&15&-20\\6&15&9&-3\end{array}\right]$

Therefore the vertex of quadrilateral A'B'C'D' is at A'(-3, 6), B'(15, 15), C'(15, 9) and D'(-20, -3).

The correct option is figure A

4 0

2 years ago

How do you do 39 divided by 936 long division

viva [34]

936 <span>39 </span>= 24

24 = 240 to the nearest tenth

24 = 24 to the nearest hundredth

24 = 24 to the nearest thousandth

= 0 to the nearest tenth

= 0 to the nearest hundredth

= 0 to the nearest thousandth

8 0

2 years ago

The variables x and y vary inversely. When y is 5, x is 3. What is x when y is 15?

koban [17]

The variables x and y vary inversely. When y is 5 x is 3, so when y is 15 x is 9.

6 0

2 years ago

You've purchased a lottery ticket and your numbers are 5-3-1. A lottery official randomly selects three balls from a set of eigh

Inessa05 [86]

Answer:

1 out of 336 chance

Step-by-step explanation:

Since you picked three numbers, you are going to put three blanks.

What to do in this situation is to have _ _ _. Since there are numbers 1-8, what you want to do is take the three biggest numbers and multiply them together. in this case, they would be 8-7-6. Multiply that and you get 336.

8 0

2 years ago

NEED HELP ASAP!!

Solnce55 [7]

Answer:

Only Cory is correct

Step-by-step explanation:

The gravitational pull of the Earth on a person or object is given by Newton's law of gravitation as follows;

$F =G\times \dfrac{M \cdot m}{r^{2}}$

Where;

G = The universal gravitational constant

M = The mass of one object

m = The mass of the other object

r = The distance between the centers of the two objects

For the gravitational pull of the Earth on a person, when the person is standing on the Earth's surface, r = R = The radius of the Earth ≈ 6,371 km

Therefore, for an astronaut in the international Space Station, r = 6,800 km

The ratio of the gravitational pull on the surface of the Earth, F₁, and the gravitational pull on an astronaut at the international space station, F₂, is therefore given as follows;

$\dfrac{F_1}{F_2} = \dfrac{ \dfrac{M \cdot m}{R^{2}}}{\dfrac{M \cdot m}{r^{2}}} = \dfrac{r^2}{R^2} = \dfrac{(6,800 \ km)^2}{(6,371 \ km)^2} \approx 1.14$

∴ F₁ ≈ 1.14 × F₂

F₂ ≈ 0.8778 × F₁

Therefore, the gravitational pull on the astronaut by virtue of the distance from the center of the Earth, F₂ is approximately 88% of the gravitational pull on a person of similar mass on Earth

However, the International Space Station is moving in its orbit around the Earth at an orbiting speed enough to prevent the Space Station from falling to the Earth such that the Space Station falls around the Earth because of the curved shape of the gravitational attraction, such that the astronaut are constantly falling (similar to falling from height) and appear not to experience gravity

Therefore, Cory is correct, the astronauts in the International Space Station, 6,800 km from the Earth's center, are not too far to experience gravity.

6 0

2 years ago