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3 years ago

If (x-7) is a factor of 2x^2-11x+k, what is the value of k

Mathematics

1 answer:

kondaur [170]3 years ago

4 0

If x-7 =0

Then x =7

Substitute x=7 into f(x):

2(7)^2 - 11(7) + k

= (98-77)+k

= 21+k

Therefore k=-21 because 21+(-21)=0

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3 years ago

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2 years ago

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3 years ago

In Brownsville Texas it is 80°F the temperature is expected to drop 1.5° each hour in Mesquite Texas is 94°F and the temperature

denis-greek [22]

Answer:

28 hours

Step-by-step explanation:

let the time period at which the temperature be equal in both Brownsville and Mesquite Texas be 'x'.

Given,

In Brownsville Texas, the temperature is expected to drop 1.5° each hour and In Mesquite Texas, the temperature is expected to drop 2° each hour.

Now, according to the question,

after 'x' hours,

⇒ 80° - 1.5°(x) = 94° - 2°(x)

⇒ 0.5°(x) = 14°

⇒ x = 28

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3 0

3 years ago

Sa = 2(pi)(r)(h) + 2(pi)(r^2) v = (pi)(r^2)(h) find the surface area and the volume.

LenKa [72]

If Sa=2πrh+2π $r^{2}$ v=π $r^{2}h$ then the surface area is π $r^{2} h$ and volume is

(rh-2h)/2r.

Given Sa=2πrh+2π $r^{2} v$ =π $r^{2}h$ .

We have to find surface area and volume from the given expression.

Volume is basically amount of substance a container can hold in its capacity.

First we will find the value of v from the expression. Because they are in equal to each other, we can easily find the value of v.

2πrh+2π $r^{2}$ v=π $r^{2}$ h

Keeping the term containing v at left side and take all other to right side.

2π $r^{2}$ v=π $r^{2}h$ -2πrh

v=(π $r^{2}$ h-2πrh)/2π $r^{2}$

v=π $r^{2} h$ /2π $r^{2}$ -2πrh/2π $r^{2}$

v=h/2-h/r

v=h(r-2)/2r

Put the value of v in Sa=2πrh+2π $r^{2} v$

Sa=2πrh+2π $r^{2}$ *h(r-2)/2r

=2πrh+2πrh(r-2)/2

=2πrh+πrh(r-2)

=2πrh+π $r^{2}$ h-2πrh

=π $r^{2}$ h

Hence surface area is π $r^{2}$ h and volume is h(r-2)/2.

Learn more about surface area at brainly.com/question/16519513

#SPJ4

6 0

2 years ago