Answer:
(x+5)²(x²+5)
Step-by-step explanation:
Given two functions x²+5 and x²+10x+25, to get their Lowest common factor, we need to to first factorize x²+10x+25
On factorising we have:
x²+5x+5x+25
= x(x+5) +5(x+5
= (x+5)(x+5)
= (x+5)²
The LCM can be calculated as thus
| x²+5, (x+5)²
x+5| x²+5, (x+5)
x+5| x²+5, 1
x²+5| 1, 1
The factors of both equation are x+5 × x+5 × x²+5
The LCM will be the product of the three functions i.e
(x+5)²(x²+5)
This hives the required expression.
Answer:
The confidence interval at this level of confidence is between 5.4455 and 12.3545.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which s is the standard deviation of the sample, which is also called standard error. So

The lower end of the interval is the sample mean subtracted by M. So it is 8.9 - 3.4545 = 5.4455
The upper end of the interval is the sample mean added to M. So it is 8.9 + 3.4545 = 12.3545
The confidence interval at this level of confidence is between 5.4455 and 12.3545.
A)
x = -y -2
y = -x -2
B)
0.5x + y = 1
0.5x + (-x -2) = 1
-0.5x -2 = 1
-0.5x = 3
x = -6
H = -0.25 I think don't really know, okay?