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12345 [234]
3 years ago
13

What is the LCM of x^2+5 and x^2+10x+25?

Mathematics
1 answer:
avanturin [10]3 years ago
5 0

Answer:

(x+5)²(x²+5)

Step-by-step explanation:

Given two functions x²+5 and x²+10x+25, to get their Lowest common factor, we need to to first factorize x²+10x+25

On factorising we have:

x²+5x+5x+25

= x(x+5) +5(x+5

= (x+5)(x+5)

= (x+5)²

The LCM can be calculated as thus

| x²+5, (x+5)²

x+5| x²+5, (x+5)

x+5| x²+5, 1

x²+5| 1, 1

The factors of both equation are x+5 × x+5 × x²+5

The LCM will be the product of the three functions i.e

(x+5)²(x²+5)

This hives the required expression.

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In a school election, Juan received 4 times as many votes as Wayne, Neal recurved twenty less votes than Juan, and Kerry got hal
77julia77 [94]

Votes received by Wayne is 112

<em><u>Solution:</u></em>

To find: votes received by Wayne

Let the vote received by Wayne be "x"

<em><u>Juan received 4 times as many votes as Wayne</u></em>

Therefore,

Juan votes = 4 times as many votes as Wayne

Juan votes = 4x  ---- eqn 1

<em><u>Neal received twenty less votes than Juan</u></em>

Neal votes = twenty less votes than Juan

Neal votes = Juan votes - 20

Neal votes = 4x - 20 ---- eqn 2

<em><u>Kerry got half as many votes as Neal</u></em>

Kerry votes = half of neal votes

Kerry votes = \frac{4x - 20}{2}  ---- eqn 3

The total votes cast in the election was 1,202

Wayne votes + Juan votes + Neal votes + Kerry votes = 1202

Plug in eqn 1 , eqn 2, eqn 3

x + 4x + 4x - 20 + \frac{(4x - 20)}{2} = 1202\\\\2x + 8x + 8x - 40 + 4x - 20 = 1202 \times 2\\\\22x - 60 = 2404\\\\22x = 2404 + 60\\\\22x = 2464\\\\x = 112

Therefore votes received by Wayne is 112

4 0
3 years ago
Gerardo says that a cube with edges that measure 10 centimeters has a volume that is twice as much as a cube with sides that mea
irga5000 [103]
He is wrong.
The 10 inch cube is bigger than the 5 inch cube by 5 cm in EACH DIRECTION.
So, the 10 inch cube should be twice as big in volume by a factor of 2*2*2
=8
Okay let's see.
5 cm cube volume = 5*5*5 = 125 cc
10 cm cube volume = 10 * 10 * 10 = 1,000 cc

1,000 / 125 = 8



5 0
3 years ago
SIMPLIFY and SHOW WORK THANKS 3∙[ 9 – 2∙ (7 – 8)]
Zepler [3.9K]

Answer:

33

Step-by-step explanation:

3∙[ 9 – 2∙ (7 – 8)]

PEMDAS,

Parentheses, start from the inside out

3∙[ 9 – 2∙ (-1)]

3∙[ 9 +2]

3* 11

33

8 0
4 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}&#10;\textit{circumference of a circle}\\\\ &#10;2\pi r&#10;\end{array}\qquad \qquad \qquad \qquad &#10;\begin{array}{cllll}&#10;\textit{arc's length}\\\\&#10;s=\cfrac{\theta r\pi }{180}&#10;\end{array}\\\\&#10;-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+&#10;\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}&#10;\\\\\\&#10;15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}&#10;\textit{area of a circle}\\\\ &#10;\pi r^2&#10;\end{array}\qquad \qquad \qquad \qquad &#10;\begin{array}{cllll}&#10;\textit{area of a sector of a circle}\\\\&#10;s=\cfrac{\theta r^2\pi }{360}&#10;\end{array}\\\\&#10;-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}&#10;\\\\\\&#10;90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
The rational expression below is also equal to _____?<br>​
Dvinal [7]
The answer is 2 bc I got it right on a quiz
3 0
3 years ago
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