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2 years ago

PLZ HELP

Mathematics

2 answers:

Vinvika [58]2 years ago

4 0

Answer:

The correct option is D) No sol6.

Step-by-step explanation:

Consider the provided equation.

$-4x-4=-4(x + 2)$

Divide both the sides by -4.

$\frac{-4x-4}{-4}=\frac{-4(x + 2)}{-4}$

$x+1=x + 2$

Subtract x from both side.

$x-x+1=x-x+2$

$1=2$

Which is not true.

Thus, the equation has no solution.

Hence, the correct option is D) No solution.

Westkost [7]2 years ago

3 0

Answer:

No solution

Step-by-step explanation:

Adding 4x to both sides of the equation gives ...

-4 = -8 . . . . . . never true

There is no value of x that will make this statement true. The equation has ...

no solution

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You and your friends going to the movies the cost of admission is $9.50 per person create a table showing the relationship betwe

kvv77 [185]

No. of People Cost

1 9.50

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3 28.50

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etc.

If we divide the cost in each row by the number of people in that row, we always have the proportion (ratio) of 9.50 / 1

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2 years ago

BRAINLIEST ANSWER GIVEN! Find the equation of the line passing through the pair points (-8,6) (-9,-9). The equation of the line

nirvana33 [79]

Answer:

y=15x+126

Step-by-step explanation:

the slope is

15 because -8-(-9) is 1 and 6-(-9) is 15 and y is over x so slope 15

To find y intercept start from -8,6 and add 15 to the y value every time you add one to the x value

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2 years ago

I can’t figure out how to use the zeros in the polynomial. Please explain

Temka [501]

Answer:

a) $P (x) = (x + 3) (x-1) (x-4)$

b) $P (x) = (2x + 5) (5x - 4) (x-6)$

c) $P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

Step-by-step explanation:

For the question a * you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

$P (x) = (x + 3) (x-1) (x-4)$

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

For question b, do the same procedure.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

$x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0$

---------------------------------------

$x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0$

--------------------------------------

$x = 6\\\\(x-6) = 0$

--------------------------------------

$P (x) = (2x + 5) (5x - 4) (x-6)$

Finally for the question c we have

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

$x = -3\\\\(x-3) = 0$

--------------------------------------

$x = 1\\\\(x-1) = 0$

--------------------------------------

$x = 4\\\\(x-4) = 0$

----------------------------------------

$x = -1\\\\(x + 1) = 0$

-----------------------------------------

$P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

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2 years ago

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nata0808 [166]

Answer:

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2 years ago

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2 years ago