Answer:
A.) 90 clockwise
E.)270 Counter Clockwise
Step-by-step explanation:
A.) Ro, -90 Rotation about the origin (0,0) 90° clockwise
(x, y) ⇒ (y, -x)
(-1, 5) ⇒ (5, 1)
E.) Ro, 270 Counter Clockwise
(x, y) ⇒ (y, -x)
(-1, 5) ⇒ (5, 1)
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
Answer:
We need to use
Step-by-step explanation:
We have to use the equation for passing through the points known as
y2-y1/x2-x1
-1-3/0-5= -4/-5
the answer is 4/5
decimal: 0.8
Answer:
6.1
Step-by-step explanation:
The area of a trapezoid is given by
A = 1/2 (b1+b2) * h where b1 and b2 are the lengths of the bases
108.6 = 1/2 ( 12+p) *12
108.6 = 6 (12+p)
Divide each side by 6
108.6 /6 = 12+p
18.1 = 12+p
Subtract 12 from each side
18.1-12 = 12+p-12
6.1 = p
