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1 year ago

OKay, i need help asap pls. The ratio is equivalent to 12/36. The ratiois not equivalent to 12/36.

Mathematics

1 answer:

EleoNora [17]1 year ago

8 0

The ratio of 1:3 is equivalent to 12/36. The ratio 3 / 4 is not equivalent to 12/36.

Given that,
The ratio__ is equivalent to 12/36. The ratio__is not equivalent to 12/36.
Blank statement to be filled from the options.

<h3>What is the Ratio?</h3>

The ratio can be defined as the comparison of the fraction of one quantity towards others. e.g.- water in milk.

Here,
12 / 36 = 1 / 3
and
12 / 36 ≠ 3 / 4

Thus, the ratio of 1:3 is equivalent to 12/36. The ratio 3 / 4 is not equivalent to 12/36.

Learn more about Ratio here:

brainly.com/question/13419413

#SPJ1

The question seems to be incomplete,
So we will fill a ratio that is equivalent to 12 / 36 and one ratio that is not equivalent to 12 / 36,
We have two ratios here 1:3 and 3:4

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How to find the derivative of cos^2x? i seem to be confused.

slamgirl [31]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2927231

————————

You can actually use either the product rule or the chain rule for this one. Observe:

• Method I:

y = cos² x

y = cos x · cos x

Differentiate it by applying the product rule:

$\mathsf{\dfrac{dy}{dx}=\dfrac{d}{dx}(cos\,x\cdot cos\,x)}\\\\\\
\mathsf{\dfrac{dy}{dx}=\dfrac{d}{dx}(cos\,x)\cdot cos\,x+cos\,x\cdot \dfrac{d}{dx}(cos\,x)}$

The derivative of cos x is – sin x. So you have

$\mathsf{\dfrac{dy}{dx}=(-sin\,x)\cdot cos\,x+cos\,x\cdot (-sin\,x)}\\\\\\
\mathsf{\dfrac{dy}{dx}=-sin\,x\cdot cos\,x-cos\,x\cdot sin\,x}$

$\therefore~~\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=-2\,sin\,x\cdot cos\,x}\end{array}}\qquad\quad\checkmark$

—————

• Method II:

You can also treat y as a composite function:

$\left\{\!
\begin{array}{l}
\mathsf{y=u^2}\\\\
\mathsf{u=cos\,x}
\end{array}
\right.$

and then, differentiate y by applying the chain rule:

$\mathsf{\dfrac{dy}{dx}=\dfrac{dy}{du}\cdot \dfrac{du}{dx}}\\\\\\
\mathsf{\dfrac{dy}{dx}=\dfrac{d}{du}(u^2)\cdot \dfrac{d}{dx}(cos\,x)}$

For that first derivative with respect to u, just use the power rule, then you have

$\mathsf{\dfrac{dy}{dx}=2u^{2-1}\cdot \dfrac{d}{dx}(cos\,x)}\\\\\\
\mathsf{\dfrac{dy}{dx}=2u\cdot (-sin\,x)\qquad\quad (but~~u=cos\,x)}\\\\\\
\mathsf{\dfrac{dy}{dx}=2\,cos\,x\cdot (-sin\,x)}$

and then you get the same answer:

$\therefore~~\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=-2\,sin\,x\cdot cos\,x}\end{array}}\qquad\quad\checkmark$

I hope this helps. =)

Tags: <em>derivative chain rule product rule composite function trigonometric trig squared cosine cos differential integral calculus</em>

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3 years ago

Let h(x)=2x−5 and g(x)=−3x+1.Find h(x)+g(x).? help please

Aleksandr-060686 [28]

This may look a little confusing but all you have to do is plug the equation given for h(x) which is 2x-5 in to the h(x) area in the equation where it says h(x) + g(x).

So far that’s (2x-5) + g(x)

Then,

Do the same with equation given for g(x) which is now,

(2x-5) + (3x+1)

Then solve,

2x - 5 + 3x + 1
2x + 3x- 5 + 1
5x - 4

Therefore the answer is 5x - 4.

8 0

3 years ago

OKay, i need help asap pls. The ratio__ is equivalent to 12/36. The ratio__is not equivalent to 12/36.

OKay, i need help asap pls. The ratio is equivalent to 12/36. The ratiois not equivalent to 12/36.