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cluponka [151]
2 years ago
12

PLEASE HELP ME ASAP!!!!!

Mathematics
2 answers:
yan [13]2 years ago
5 0

Answer:

67º <33

Step-by-step explanation:

180-46= 134º

134/2= 67º

FromTheMoon [43]2 years ago
3 0

Answer:

x = 46

Step-by-step explanation:

The two strokes on the triangle show that those two sides are equal. Thus, the angle at the bottom left is equal to x.

x = 46°

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What is 1/4+2/3 equal
Alexxandr [17]

Answer:

0.91666666666

Step-by-step explanation:

1/4 + 2/3 = 0.91666666666

3 0
3 years ago
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You are knitting a blanket. You want the area of the blanket to be 24 ft². You want the length of the blanket to be 2 feet longe
Finger [1]
With the facts you got here, you can make the following equation:

x*(x+2)=24

x^2+2x=24
x^2+2x-24=0

Then you can use the following formula (which you might have seen before):
x = (-b +/- sqrt(b^2-4ac))/2a

where
ax^2+bx+c=0

(-2 +/- sqrt(4+96))/2
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3 0
3 years ago
You are given a box of 100 silver dollars, all facing heads up. You are instructed to shake the box 2 times; after the second sh
Nimfa-mama [501]
100 divided by 2 is 50 and then divided by 6 is 8.333333 but you just round that to 8$.
8 0
3 years ago
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The equation 320=x+7.50(36) represents the cost of ordering potted plants at a second store.
anygoal [31]

Answer:

I would say it's the amount of potted plants.

Step-by-step explanation:

x is the independent variable and y is the dependent variable. Y counts on x, so total cost counts on the amount of potted plants.

3 0
3 years ago
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Restless Leg Syndrome and Fibromyalgia
mixas84 [53]

Answer:

The probability that a person with restless leg syndrome has fibromyalgia is 0.1833.

Step-by-step explanation:

Denote the events as follows:

<em>F</em> = a person with fibromyalgia

<em>R</em> = a person having restless leg syndrome

The information provided is as follows:

P (R | F) = 0.33

P (R | F') = 0.03

P (F) = 0.02

Consider the tree diagram attached below.

Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:

P(F|R)=\frac{P(R|F)P(F)}{P(R|F)P(F)+P(R|F')P(F')}\\\\=\frac{(0.33\times 0.02)}{(0.33\times 0.02)+(0.03\times 0.98)}\\\\=0.183333\\\\\approx 0.1833

Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.1833.

6 0
3 years ago
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