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Gala2k [10]
3 years ago
8

Are these ratios equivalent?

Mathematics
1 answer:
masya89 [10]3 years ago
3 0

Answer:

A, yes.

Step-by-step explanation:

63:60, 21:20:

The difference between 60 and 20 is *3. If you do that to 21, you get 63. So a , yes.

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Find 50% of 36:<br> Find 25% of 36:<br> Find 75% of 36:
HACTEHA [7]

Answer:

18, 9, 27

Step-by-step explanation:

36 ÷ 2 = 18. Dividing by 2 is the same as multiplying by 50%.

36 ÷ 4 = 9. Dividing by 4 is the same as multiplying by 25%.

Since 25% • 3 = 75%, you can do 9 (from previous) • 3 to get 27.

5 0
3 years ago
On the first week of class, Lisa reads 45 pages in her history book. It takes her 8 minutes to read. The next week she reads 36
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I wanna say C  not positive but I think C

Step-by-step explanation:

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3 years ago
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Dr. Hall files 320 insurance claims every month.5% if those claims are rejected, how many claims are rejected? how many are acce
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5%=0.05
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8 0
3 years ago
I don’t understand the equation
ankoles [38]

you need to find to find the value of x and y.

2x>(-15-5y)

x>(-15-5y)/2

now put this in to other equation and solve for y and then put the y value in and find x.

6 0
3 years ago
A gas station stores its gasoline in a tank underground. The tank is a cylinder lying horizontally on its side. The radius is 5
atroni [7]

Answer:

The exact work required to pump all the gasoline to the surface of the ground is π × 5.094 × 10⁶ j

Step-by-step explanation:

Here, we note that volume of a slice is given by

Length × Width × Height

Length of slice = Length of cylinder = 15 ft

Since the slice height is Δy ft thick and located y ft above the center of the cylinder, then

Width of slice = 2 × √(r² - y²)

Where:

r = Radius of the cylinder =5 ft

∴ Width of slice = 2 × √(25 - y²)

∴Volume of slice = 15 ×2 × √(25 - y²)×Δy

Mass of slice then = 42 × 15 ×2 × √(25 - y²)×Δy = 1260 × √(25 - y²)×Δy

The force required to lift the slice is the weight of the slice, which is given by

32.2 × 1260 × √(25 - y²)×Δy = 40572 × √(25 - y²)×Δy N (Newtons)

The work done by the force is the product of the force and the distsnce through which the force acts.

Work done = 40752×(10-y) × √(25 - y²)×Δy

Therefore total work done is given by

W = \int\limits^5_{-5} {40752\times (10-y) \times \sqrt{ (25 - y^{2} )} } \, dy

 

= 5094000·π J = π × 5.094 × 10⁶ j

The exact work required to pump all the gasoline to the surface of the ground = π × 5.094 × 10⁶ j

6 0
3 years ago
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